Chikis

How do I evaluate [math]9.9\times10^{-26}-2.0[/math]?

[MATH]\frac{1}{m-1}+\frac{9}{2m+3}-\frac{8}{m+4}[/MATH] = [MATH]\frac{(2m+3)(m+4)+9(m-1)(m+4)-8(2m+3)(m-1)}{(m-1)(2m+3)(m+4)}[/MATH] = [MATH]\dfrac{2m^2+8m+3m+12+9m^2+36m-9m-36-16m^2+16m-24m+24}{(m-1)(2m+3)(m+4)}[/MATH] = [MATH]\frac{30m-5m^2}{(m-1)(2m+3)(m+4)}[/MATH] = [MATH]\frac{5m(6-m)}{(m-1)(2m+3)(m+4)}[/MATH] Am confident that this one is very correct. Thanks for the caoching. Thanks for the tip.

Please help me. What mistake am making that am not getting the right thing?

I go again:[MATH]\dfrac{(2m+3)(m+4)+(9m-9)(m+4)-(16m+24)(m-1)}{(m-1)(2m+3)(m+4)}[/MATH] = [MATH]\dfrac{46m+11m^2-32}{(m-1)(2m+3)(m+4)}[/MATH] Is the numerator okay now?

[MATH]\frac{1}{m-1}+\frac{9}{2m+3}-\frac{8}{m+4}[/MATH] = [MATH]\frac{(2m+3)(m+4)+9(m-1)(m+4)-8(2m+3)(m-1)}{(m-1)(2m+3)(m+4)}[/MATH]= [MATH]\dfrac{2m^2+8m+3m+12+9m^2-9m+36m-36-16m^2+m-24m+24}{(m-1)(2m+3)(m+4)}[/MATH]= [MATH]\frac{5m(3-m)}{(m-1)(2m+3)(m+4)}[/MATH] What next should be done?

I have managed to complete the diagram. The diagram has the description: triangle QPR. <QPR = [latex]140^0[/latex]. QP = 20km and PR = 8km. I first used cosine rule to find PR, which I got as 14.79km. I again used cosine rule to find <PQR - bearing of R from P, which I got as [latex]20^0[/latex] to the nearest degree. Now, how do you see my work? As for the second part of the question (b), am yet to understand it fully. How do they mean by "how far north of P, R is". From the way I look at it, in the diagram Q is 20km north of P. Or do they mean the distance PR, which I got as 14.79km?

Thank you for the help. But I still have problem completing the drawing to show the bearing of R from P. Please can you complete it for me or just describe how I can do it?

Example 1 [latex]5/3 /4|5[/latex] Example 2 [latex]4/8/2|17[/latex] Example 3 [latex]13/7/4|5[/latex] What are the relationship in the example? Use the relationship to solve for the missing number? [latex]?/5/3|17[/latex] just a repost:-)

Example1 5/3 /4|5 Example2 4/8/2|17 Example3 13/7/4|5 What are the relationship in the example? Use the relationship to solve for the missing number? ?/5/3|17

The rule given seems not to work with?[latex]1.2+5 => y ?[/latex] [latex]3+2 => z ?[/latex] You cannot use the rule to find y and z respectively.

That's right. You got it! That is to say that 7 is a kind of identity in the relationship.

Example [latex]5+2 => 1[/latex] [latex]8+6 => 2[/latex] [latex]6+4 => 1.3[/latex] What is x in [latex]4+4 => x ?[/latex]

Town Q is 20km due north of P. The bearing of town R from Q is [latex]140^0[/latex]. If R is 8 km from Q. calculate: (a) the bearing of R from P, to the nearest degree: (b) how far north of P, R is, correct to 2 significant figures; Drawing the diagram is my main problem. If you can help me with the drawing, I can attempt the working.

Thank you for that info. But I want to specifically know how to use latex in the forum when preparing a thread.

How do I indicate or show square root sign, super script and sub script? How do I use latex in the forum? E

Thank you.

I want to understand the following terms 1. Local password 2. Current password 3. Display name. I also want to know how to go about it should I decide to change my username.