Brazen

Nope, never heard of the rule of 13, and ty for telling me about it helped. according to the rule of 13, if i did it correctly I have C10H13O, i calculated degree of unsaturation and i got 4.5, don't know what to make of the number. since it is not the whole number. as for the integration if i did it correctly, i think that peak after seven have five H, peak before four have two H, peak before three have one hydrogen, peak right after one have two hydrogen, then the next three hydrogen and the last one H from OH. Does this look right?

Chem: can someone tell what the structure is? I see from IR spectrum that I have OH, C-H sp2, C-H sp3, C=C aromatic, C-O groups. I see that I have 91, 134, and 149 fragments. I know that 91 is benzene-ch2+ fragment. I don't know what the 134 or 149 fragments are. I know that 149 is actually the whole structure. Looking at proton and C13 NMR i see that i have OH, benzene, CH3, CH2, CH groups, not sure if i got all of those groups right. I can't seem to get what the structure is. Here is spectra: http://i39.tinypic.com/zmjypd.png http://i44.tinypic.com/wkst91.jpg