studiot

Whilst I fear the OP has already abandoned this thread, I remain usure of your meaning. Where does this energy come from ?

Well yes, you would say somewhere else that you were dealing with real numbers. If you wanted to be strict, or just starting you could add a second condition [math]M = \{ x:1 < x < 2:x\;real\} [/math] or [math]M = \{ x:1 < x < 2:x\; \in R\} [/math] or as many conditions as you needed for that situation. Edit : Sets are usually shown as upper case and members as lower case (as you have done) I will wish you goodnight on that.

Set theory notation is not my speciality, but I am used to the following, which is very common. [math]M = \{ x:1 < x < 2\} [/math] or [math]M = \{ x|1 < x < 2\} [/math] Which read in English M is the set of all real numbers, x, which obey the given condition ie greater than 1 but less than 2. I am sure there are other notational variations, but you need the colon or vertical line to separate the variable x and the condition. The list of members or the variable+condition are usually enclosed in parenthesis type brackets.

Look at my edit/ addendum to my previous post. Don't be sorry, this is a perfectly respectable discussion.

You need to distinguish between set enumeration (the number of members of a set) which may be infinite and the extremal values taken on by those members ( the bounds of the set) which will be finite if bounds exist. Does this help? Edit Some good models can be drawn from the set of all real numbers. This is unbounded and infinite (ie contains an infinite number of members) The set of real numbers greater than 1 and less than 2 is a subset of the reals that is still infinite but bounded above (by2 ) and below (by1), although neither 2 nor 1 belong to the subset. The real number 1 is finite and a finite subset of the reals. tan(90) is unbounded, but a finite subset (it contains one member)

Ah the good old days! When every instrument (compass, ship's chronometer, voltmeter, post office test box etc) came with an calibration chart to be applied to correct the reading. Perhaps SF is like that. I must observe that this problem does not occur on other forums I visit.

Yes, changing to West African time does seem to work. Perhaps its soemthing to do with relativity Thanks

My timezone is GMT and there is currently no allowance for summertime. I have tried all the settings I can find, but the listings persistently show timings of posts to be 1 hour ahead, whatever settings I choose. How do I set the time correctly please?

How does this work? Are you implying that this heat passes from the car to the surroundings during the manufacturing process?

If the membrane is permeable to all species it might as well not be there and osmosis does not occur. Osmosis occurs when there is a semipermeable membrane that is permeable only to some of the species involved.

This might give you some ideas https://www.google.co.uk/#q=electrophoresis

Here is a worked solution

Anyone know anything about the chemistry of these? http://www.canadianmanufacturing.com/design-engineering/news/re-chargable-sugar-based-battery-outperforms-lithium-ion-researchers-say-130456?utm_source=DNG&utm_medium=email&utm_campaign=DNG-EN01232014&e=8wq4zW4r20u4M20

What if the IP is a school with some good guys and some bad?

The best thing I can suggest is to get hold of some books that are not meant for mathematics directly, but use maths, choosing suitable subjects that might interest you. These are often called 'practical maths' and cover stuff like measurement, area, weights and so on. Look for some basic surveying, mechanics, carpentry and the like in your local or school library. See what you can understand and what you need to know more about. then come back and say "I found this formula in my book on ...... how does it work?" The 'demystified' series of books from America, and the 'Teach yourself' series from England are both good. The solid geometry books in the other thread you were looking at are at a much higher level.

What makes you think any product (including a car) is 'well ordered'. How do you define this state of bliss? The relationship between order, entropy and statistics is widely misunderstood.

The most important thing of all is that you do not learn maths by reading and particularly you do not become proficient at it that way. You learn by doing. Yes some reading or other source of instruction (teacher, Internet, friends etc) will provide material but do not try to read too much theory before doing lots and lots of practice. By 16/18 you should surely know more than add/subtract/multiply/divide. You surely know some geometry such as stuff about circles and squares? Give us a bigger clue as to your range and intended applications.

My solution makes p+q+r = 12. I think the quadratic is a red herring that you do not need. Although the answer comes out easily in a few lines, I'm amazed they consider it useful for medical studies.

Whilst the 100g mass is a desireable accessory, you can improvise if you have access to another balance, by weighing something you can keep for the future, eg a box of lead shot, and comparing. You could actulally make and prepare several test weights this way. The 100g g test weight is obviously needed for commercial applications.

Yes that's it. But this theorem leads to a number of results. Since your quadratic is one of the factors of the original quartic,(x=k, x=l, x = m, x=n ), any solution of the quadratic is also a solution of the quartic. So this gives you additional equations to connect p, q and r. Further the two solutions (x=k and x=l) of the quadratic ax2 + bx +c have the folowing properties (k+l) = -b/a (note the negative) kl = c/a Which also supply equations connecting p, q and r

Are you familiar with the remainder theorem?

There's lots of science you can do that would cost you nothing or next to nothing. But I hesitate to offer anything since I don't know how my suggestions will be received. Perhaps if you indicated what interests you, you might receive some ideas.

Careful, Perpetual motion machines are impossible......... But see Newton's First Law Perpetual motion is possible in an appropriate system.

I make the constant term of your quadratic to be (9r-18).

When you derive the wave equation acting in a system you do not use the external input force. You use the restoring force, which is due to the mechanics of the system. The wave action is due to the presence of this restoring force, If the restoring force is proportional to the dispalcement you obtain the linear solutions you indicated. The input force is used to provide an initial displacement and does not appear directly.