Thank you for replay.
If I consider uniformly charged infinite disc, lines of electric field are perpendicular to it. Then, I can use any symmetrical Gaussian surface and find out that electric field doesn't depend on distance. Now, If I treated my crystal as a set of parallel, infinite and charged uniformly, positively and nagatively discs arranged alternatelyelectric field outside would be zero - that is okay.
The thing is, a point very close to the surface doesn't "see" nearest part of the crystal as uniformly charged. I expect differences in electric field depending on positions in the surface plane - in the same distance but above positive or negative ion.
I wonder, is a reason why I should differently consider ions in the surface plane then in deep (cylindrically), not uniformly in all directions (spherically)?
Best regards,
Aksonik