Salazar

I appreciate all the input, thanks allot.

I only have the initial velocity (Vi2) after the time interval of 3 seconds with a traveled distance of 50.0m (Vi2)(cosα)=50m/3s= 16/67m/s). This helped me get the initial velocity (Vi) after the ball was hit (Vo=Vf-at; Vo=16.67m/s+(9.8m/s^2)(1s)=26.47m/s). But I have no angle so how do I find the x-component of velocity to get the distance traveled in that one second interval (with the equation (Vx=Vo(cosαα)?

Help, I am having a difficultly setting up this problem. A baseball is hit at a height H=1.00m and then caught at the same height. It travels alongside a wall, moving up past the top of a wall 1.00s after it is hit and then down past the top of the the wall 4 seconds later, at a distance D=50.0m farther along the wall. Find : (A) Horizontal distance traveled from hit to catch.