The outer core is the shock absorber of the system, it is the inner core that is locked to the moon, so from its outer surface to the outcore/mantle boundary is the "transition zone. A proof for this would be to place a large (1200 km dia) conductor in the polar region. 78 degrees is the prefered aurora position, as well as the "magic angle" of 54.7 deg. (look up magic angle!). An easy test would be a few circles of 2.9 km diameter overlapping by 1/4 of circumference. I think it will not only produce electricity, but will also exhibit some super-conductive levitation! There is a record of an approx. 11 km drift per year of "pole position" (which on its own should cause induction.
cheers
in short NO, the atmoshere is trivial to the earths mass and the upper atmosphere has nothing to push upon. The power comes from the core and all above are controlled by its mass and magnetic moment.
The outer core is the shock absorber of the system, it is the inner core that is locked to the moon, so from its outer surface to the outcore/mantle boundary is the "transition zone. A proof for this would be to place a large (1200 km dia) conductor in the polar region. 78 degrees is the prefered aurora position, as well as the "magic angle" of 54.7 deg. (look up magic angle!). An easy test would be a few circles of 2.9 km diameter overlapping by 1/4 of circumference. I think it will not only produce electricity, but will also exhibit some super-conductive levitation! There is a record of an approx. 11 km drift per year of "pole position" (which on its own should cause induction.<br style="font-size: 13px; line-height: 16px; background-color: rgb(248, 250, 252); ">
in short NO, the atmosphere is trivial to the earths mass and the upper atmosphere has nothing to push upon. The power comes from the core and all above are controlled by its mass and magnetic moment. The symmetries of rotation with the sun are also impressionable