NerDyPhyisicst

So what I did was just added the two vectors (10 i + 20j) + (-5i + 10J) and got 5i + 30j . Since a= Fnet/ m I divided 5i + 30j by 5 and got i + 6j (a). However I'm not confident about my answer because it seems too straightforward.

Oh so that's what it meant. Thanks for the clarification...!!

Question is in attachment So the formula I used was F= ma = F= mdelta v / t 10i + 20j = 5 kg(Vf-(-5i+30j)/10 I got 10i +20j = 1/2vf( -5/2i+15j) = (15i + 70j)m which is C. However the question says the object is located in the origin of reference frame and asks to find the position of the object which I don't understand how to do :/ Oh a piece of the question got cut off. The question is "What will be the position 10 seconds later"?