amjad905
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Hi, i have a question change P <-> Q into dnf and cnf which i believe that it is below...correct me if i am wrong.... i). p<->Q = (P->Q) ^ (Q->P) this is the DNF form ii).¬(¬P->¬Q) ^ (¬p->¬Q) this is the cnf form am i correct??if not then explain why plz...