hellomister

Thanks, that was a good explanation, I forgot a lot of gchem and my inorganic professor didn't really explain that much.

All i know is that its more stable, but does anyone know exactly why? and when you write the electron configuration of a transition metal in a complex do you write the configuration in the order that its filled or do you still write the s in front of the d?

Can someone explain to me why the d-orbitals of a transition metal when they are in a complex are filled before the s-orbital? thanks. * i also have another question* How come the maximum oxidation state of Ni does not exceed 4 since it has many more valence electrons than 4.

Hey all, I'm not sure exactly where I should post this, so my apologies if it is in the wrong area of the forum. I am going to be taking physical chemistry next year and I was wondering how the material is? So far, everyone i've asked said it was: 1. tough 2. lots of physics 3. lots of chemistry Thank you for your input. -A grateful chem student

Thank you very much, I ended up doing the reaction for a base catalyzed reaction and while drawing the mechanism I realized I could also do something else at the anhydride part of the molecule. I think I have figured it out since it corresponds to my NMR data.

Hey all I was wondering what the expected product should be in this reaction, everywhere i looked says it will be the same product as for the base reaction, but I dont think that is right. The product I predicted was having an acyl group on the anhydride substitute for the hydrogen on the aldehyde part of Vanillin. Can anyone tell me if this is correct? thank you.

LiAlH4 reduces aldehydes and ketones to their corresponding alcohols.

in response to the original poster, organic chemists use spectroscopy to identify the compounds they make. I.E. HNMR, CMR, IR, UV/vis. All you really need is NMR's though and an IR maybe.

Hi guys, I was wondering if a second nitration of p-nitrobromobenzene would work using a catalytic amount of H2SO4. I was thinking it wouldn't since both the bromine and the Nitro group are deactivating substituents, and since its a catalytic amount of acid it wouldnt add a second nitro group onto the ring. Is this reasoning correct?

hmm is it even possible to classify light as chiral or achiral? haha?

hmm i'm confused, i have never tried to classify something such as light as chiral or achiral. I have only done this to molecules. So light is not chiral because of its properties of wave-particle duality? since you said photons treat all polarizations equally. By the way what's a fermion? thanks.

i thought if a chiral molecule has any type of symmetry it is deemed achiral.

Since it can be polarized in different planes does this mean is chiral? if light can help us determine which substances are chiral then it has to be chiral right? since only chiral objects can identify other chiral objects.

I think light is chiral because it can be polarized in a clockwise or counterclockwise direction. Is this correct?

haha thanks! helped a lot!

I have a question, is there a way to determine if two things are diastereomers by looking at their R/S configurations at the asymmetric atoms? Because so far I have been just rotating molecules in my head and it is very slow. ty.

Oh i think I understand, thank you. Um sorry it is indeed a textbook question but it is not a homework assignment, our teacher said to do it for extra practice, and I couldn't figure it out. Thanks and sorry if it was in the wrong spot.

is it because both groups are in the equatorial position most of the time? so there are no 1,3 diaxial interactions with either group?

why is the energy difference between conformations of ethylcyclohexane is about the same for methylcyclohexane even though the ethyl group is larger than the methyl group? thanks!

oh i just assumed that if it was on one of the other non double bonded carbons you would put a number to indicate that, thanks for clarifying!

In a cyclic alkene with one double bond and a methyl group on the carbon of that double bond, is it necessary to state the position of the methyl group? Do i really need to write 1-methylcyclobutene for instance?? wouldnt you just assume the methyl group is on the first carbon of the double bond? if you didnt have a number? Thanks.