Kangaroo

You are correct thank you.

Sure, I know E=MC^2 has something to do with it. As I have solved the joules for the mass of 3.48*10^-28kg by doing 3.1*10^-11/1.602*10^-13=193.5 MeV So I thought If I rearrange the equation to E*C^2=M however that seems not to work. Thank you.

Hi there, I am hoping someone could help me through this: Q) During the radioactive decay of cobalt-60, a gamma ray with 1.33 MeV of energy is released. Calculate the decrease in mass (in kg) of the cobalt-60 nucleus as a result of this emission. A) 2.36*10^-30 I will ask the teacher tomorrow and reply back here with the strategy if no one knows this. Thank you.