Asimov Pupil
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i have two questions 1. what about the expantion of the excelleration from the spinning, or is it so negligable that the "gravity" cancels it out 2. how does that prove that pi ceases to be a constant
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as i recall, it is the occilation period of the string that determines wether it is a mass particle or a messenger particle (i think). would the spinning of a messenger string give it different property?
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Flow of Electric charge
Asimov Pupil replied to Primarygun's topic in Modern and Theoretical Physics
Would it have the same effect as standing on you with bare feet or with high heels (and believe me that hurts)? i guess my point is that it is the same amount of energy transfer but instead of occuring over, maybe, [math]2cm^2[/math] its over [math]1mm^2[/math] though it's very early and i don't have the time to calculate that ratio in my head. -
ok so is it the same type of plasma but in a supercooled state?
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National Geographic has just published an article about fusion reactors. and it states that at about 100 million degrees Centigrade a gaseous state of plama forms in and around the hydrogen. can some one explain the process and why that happens. and what is cold plasma, is it related to cold fusion?
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Antigravity phenomena
Asimov Pupil replied to Asimov Pupil's topic in Modern and Theoretical Physics
The book is called atlas of the skies i got my dad for christmas. the scientific consultants were Prof. Fabrizio Mazzuccoi and the ARCE Astrophysical observatory in florence. That is the full quote. it was in bullet form -
Antigravity phenomena
Asimov Pupil replied to Asimov Pupil's topic in Modern and Theoretical Physics
what are higgs fields? -
can anyone give me any information on the mascons thank you
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Antigravity phenomena
Asimov Pupil replied to Asimov Pupil's topic in Modern and Theoretical Physics
ok i will research more into this matter thank you -
Antigravity phenomena
Asimov Pupil replied to Asimov Pupil's topic in Modern and Theoretical Physics
i understand and maybe they messed up their words but lets not pick apart words here. a negative gravitational phenomena sounds to me like a mass that repels instead of pulls. and the reason i say that is because they mention the meteiorite. -
Antigravity phenomena
Asimov Pupil replied to Asimov Pupil's topic in Modern and Theoretical Physics
as an after thought it isn't [math]-9.81m/s^2[/math] on the moon. i forget what it is though. but you get what i mean? -
Antigravity phenomena
Asimov Pupil replied to Asimov Pupil's topic in Modern and Theoretical Physics
ah but it says NEGATIVE GRAVATATIONAL phenomena so if their both negative it is a positive phenomena no? -
i have a book that discusses lunar geology and states about craters "frequently shows negative gravitational anomalies due, probably, to the subterranean pressence of the meteorite" please explain
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how bout -49.5? do you round to -50 or -49 or is "rounding up" an improper term.
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I'm afraid i am not seeing something help would be apreciated. you toss a stone upwards off a 63m cliff at 8 meters per second how long til it hits the ground? here is what i have [math]a=-9.8\frac{m}{s}[/math] then the velocity using antiderivatives is [math]v=-9.8t=8[/math] and distance [math]s=-4.9t^2+8t+63[/math] then if [math]s=0[/math] [math]t=4.49sec[/math] my question is that if you throw a stone upwards off a cliff then wouldn't the C value in the s formula be higher than that? what am i missing?
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what about slingshoting rockets around planet's and stuff. we do that. so we can harness gravity but can we saddle and train it
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thank you
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oh ok
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sorry to bother everyone but i found a question to which i never learned process so i wonder if anyone can tell me da rules or explain it to me [math]f(x)=e^{2x)[/math] find [math]f^6(0)[/math] though i think this is a fundamental technique I must have missed it when they were teaching it. so i checked the book and it said the answer was 64 now the only way i could get it to equal that, is to find the derivative [math]\frac{dy}{dx}=2e^{2x}[/math] then solve f(0) [math]f(0)=2[/math] then i thought that [math]f^6(0)=(f(0))^6[/math] so i did [math]2^6=64[/math] i'm not sure if my process is right (which i think it isn't cuz it didn't say [math](f^6(0))'[/math]) someone please explain thx
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well the way i see it you can calculate an angle thaeta to find the value of the oposite side which is a side of the Square then the area is (x)^2 cuz according to calculus the max area is is a square
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well we know that the max area for a retangle is a square right? so now into the calculus! gimme a while
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[math]y=e^{sinx}[/math] find [math]\frac{dy}{dx}[/math] i know it equals [math]e^{sin(x)}cos(x)[/math] very easy question but my teacher did it out in her haed so i want to see the right prosess
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i'm in calculus and am taking a test tomorrow what section?
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an analogy to the red/blue shift is the doppler effect for sound. If it comes towards you it's higher pitched and the opposite holds true i know this isn't what happens with light but it's just an analogy.