feign_ignorence

I think this should be under 'Applied Chemistry' (?) but one possible way (industrial) is: the Claus process

I definately don't agree that some actors (or any actors) should be as exuberantly rich as they are, and filmmakers should take advantage of the ton of people who want to try to get into acting instead of rehashing flicks with the same boring actors... However, actors are employed by demand in the hopes that they'll make the movie more profitible so i suppose this doesn't matter. Also: Couldn't you have picked another actor to make this thread about? Nicolas Cage is a pretty decent in his movies... if you're gonna bitch, rant about Tom Cruise or some other twat!

What kind of loon would make a ring in the shape of a watch?

Thank you for enlightening me with this thread

pretty fun i like the skyscraper game... gave up at 8 letter words though:doh: they do help though: spacial recoginition, vocabulary, memorization, reasoning...etc

Regardless if you decide to choose a career that involves 'calculus'; i've always though it beneficial just to go through learning something because you 'can'. What use is history to the majority of the students? Geography? Compulsory language courses? We forget most of the stuff we learn in school that we don't complement with follow-up courses, but the process of learning certain things makes us more capable people, and trains our brains.

[math] (x^2-3x+2)(\tfrac{1}{2}x^\frac{-1}{2})+(2x-3)(x^\frac{1}{2}) [/math] [math] (x^\frac{4}{2}-3x^\frac{2}{2}+2)(\tfrac{1}{2}x^\frac{-1}{2})+(2x^\frac{2}{2}-3)(x^\frac{1}{2}) [/math] Multiply the terms through [math] (\tfrac{1}{2}x^\frac{3}{2}-\tfrac{3}{2}x^\frac{1}{2}+\tfrac{2}{2}x^\frac{-1}{2})+(2x^\frac{3}{2}-3x^\frac{1}{2}) [/math] Group terms with the same exponent ie:[math]x^\frac{1}{2}[/math] [math] (\tfrac{1}{2}x^\frac{3}{2}+2x^\frac{3}{2})+(-\tfrac{3}{2}x^\frac{1}{2}-3x^\frac{1}{2})+x^\frac{-1}{2} [/math] Only have one of each 'type' of x [math] (\tfrac{1}{2}x^\frac{3}{2}+\tfrac {4}{2}x^\frac{3}{2})+(-\tfrac{3}{2}x^\frac{1}{2}-\tfrac{6}{2}x^\frac{1}{2})+x^\frac{-1}{2} [/math] [math] (\tfrac{5}{2}x^\frac{3}{2}-\tfrac{9}{2}x^\frac{1}{2}+x^\frac{-1}{2}) [/math] Reduced form: [math] \tfrac{1}{2}x^\frac{-1}{2}(5x^\frac{4}{2}-9x^\frac{2}{2}+2) [/math] [math] \tfrac{1}{2}x^\frac{-1}{2}(5x^2-9x+2) [/math] (done here) If that ended up to be -2 instead: [math] \tfrac{1}{2}x^\frac{-1}{2}(5x^2-9x-2) [/math] It can be factored like this: [math] \tfrac{1}{2}x^\frac{-1}{2}(5x+1)(x-2) [/math] I think that's right.

^-----Yes. You should check with your university (couse syllabus if you have access) before you purchase a calculator. Once you find out which types you can't use (more often than not you can only use what they tell you). (i recommend Casio991 for physics; usually you don't get to use calculators on math tests)

Wikipedia is generallly accurate but if you're serious about using the information presented you should click the sources at the bottom of the page... I've always found teachers' disapproval to the 'use' of wikipedia to be unnecessary.

You should start by explaining what you actually think the above professions are and what they mean to you. You're only 15 so i wouldn't focus on 'choosing what you wan't to be' asmuch as trying to find out which field of study you love! Take the time to research the prerequisites for the programs you think you might apply for (school guidance councillor) as well... Regardless of which profession you decide to follow, try to include the following in your course selection (all are requisite to those 4 things you have listed except biology, but biology is fun): upper level math, physics, biology and chemistry. Economics, and law could help too.

Thanks for that link for LaTeX Lets try this again! I hope my explaination makes a bit more sense now...

(x^2-3x+2)(1/2x^-1/2)+(2x-3)(sqrt x) [(x^4/2)-(3x^2/2)+(2)][(1/2)(x^-1/2)]+[2x^-6/2][x^1/2] Its a bit hard to show using text, but its just basic exponent multiplication. Same base = add the exponents. Add the exponents by putting both x^ into the same denominator (in this case 2 on the bottom). For example: (x^2)((1/2)(x^-1/2) -> (x^4/2)((1/2)(x^-1/2)) it becomes (1/2)(x^[4/2-1/2] => (1/2)(x^3/2) Its much easier to understand if you write it on paper!

Expand and simplify

"To fight for justice anywhere is to fight injustice everywhere" -unattributable

Site worked. Hard to even determine the gender of some of those people given the closeness.. I rated about 12 women before i exited the browser out of guilt for rating these ladies so poorly:( edit: also theres a girl in there with a piece of plastic nailed through her nose and looks like she should really seek medical attention