Swanson, the person who is measuring the speed is on object A. Isn't it his time that matters in the velocity calculation.
md65536 let me rephrase the question this way. Supposing there are two stationary objects A and D and object B is moving toward D and a light is being shown from A on B and from D on B. The clocks on A and D are moving at the same speed. Lets say the clock on B is moving slower than on D. That means the clock on B is moving slower than on A since the clocks on A and D are the same. If that were the case though you would measure one of the light beams as going faster than the speed of light.