Need help solving the mass of 9.01 x 103 mole CF4(g)

[CuriousStudent]

The full question is: "What is the mass of 9.01 x 103 mole carbon tetrafluroide, CF4(g)?"

Any help on explaining how to get the answer to this is much appreciated.

[StringJunky]

The full question is: "What is the mass of 9.01 x 103 mole carbon tetrafluroide, CF4(g)?"

Any help on explaining how to get the answer to this is much appreciated.

Do you know what a mole is? See if you can work the problem out with this definition of a mole:

 

 

The mole is the unit for amount of substance. The molar mass is the relative formula mass of a substance in grams (measured in g/mol).

Edited November 5, 2016 by StringJunky

[CuriousStudent]

Do you know what a mole is?

I have a vague idea of what it is. I am new to the concept of molar mass and what not.

[StringJunky]

You need to find out the molar mass of the compound, which is in grams, and multiply that by the number of moles given. You then multiply that result with the left side of the sum. The molar mass is the combined atomic mass, expressed directly in grams, of each element in a compound.

Edited November 5, 2016 by StringJunky

[CuriousStudent]

Thanks, that helped more then what my textbook can explain to me.

[StringJunky]

Thanks, that helped more then what my textbook can explain to me.

No problem.

[Sensei]

You need to find out the molar mass of the compound, which is in grams, and multiply that by the number of moles given.

 

Molar mass is in [math]\frac{g}{mol}[/math] units.

 

After multiplication by moles, you get simple grams, because mol^-1 (denominator in g/mol) and mol cancel each other.

[math]\frac{g}{mol} * mol = g[/math]

 

The molar mass is the combined atomic mass, expressed directly in grams, of each element in a compound.

Atomic mass is in a.m.u (mass atomic unit), shortcut u. It's approximately 1.66*10^-27 kg.

After multiplication by 1000 (to get grams) and multiplication it by Na (Avogadro constant), you get g/mol.

Which is very large number of atoms or molecules (6.022141*10^23).

 

f.e. 12 u * 1.66*10^-27 kg/u * 1000 g/kg * 6.022141*10^23 mol^-1 = 12 g/mol

Edited November 5, 2016 by Sensei

[Sriman Dutta]

Is CF4 carbon tetrafluoride ??

[CuriousStudent]

Is CF4 carbon tetrafluoride ??

Yes.

[StringJunky]

Is CF4 carbon tetrafluoride ??

Tetra means 4.