Enski Posted May 14, 2005 Posted May 14, 2005 Well to begin . I'm crap at maths and I have a test after the weekend is over , I didn't turn up to maths class the other day and now I missed out and forgot what I'm supposed to know about in/equations . darn . If anyone can spare a little time explaining to me how I'm suppose to approach : Simultaneous Solutions Gradients intercepts With an example to use : inequation : 3x-5y<15 and equation : 2t-4c=11 It would very nice of you .. thanks heaps in advance
albertlee Posted May 14, 2005 Posted May 14, 2005 You are like saying, "how am I approached to English Punctuation". I can tell you what is intercept and gradient, but not system of equation, it is just something flexible in the sense of mathematical logic, making algebraic term meaningful to you, and thus form a meaningful serie of equations to solve certain problem. 1) intercept, the y value, which the line cross the y axis. For example, y = x+5, if x is 0, the point situates at y value 5, which is the intercept, or y= x2 + x - 2, then if x is 0, -2 is the intercept, again, where the line cross the y axis. 2) gradient, as simple as: (y value - intercept)/(corresponding x value) Respond if you dont understand Albert
albertlee Posted May 14, 2005 Posted May 14, 2005 I feel you should make some efforts on yourself, asking you teacher, for example. With an example to use : inequation : 3x-5y<15 and equation : 2t-4c=11 It would very nice of you .. thanks heaps in advance nonsense.
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