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Posted

Hi,

 

The following reaction(see photo attached) was talked about on a lecture I watched on YouTube.

There was no mechanism mentioned so I tried to work it out myself.

Can you confirm if I'm on the right track?

 

Firstly the Na H (in excess) would de protonate all of the OH groups on the glucose molecule.

 

Then the now O- groups would react by SN2 pathway on the benzyl chloride molecules. Now all the former O- groups would be joined to benzyl CH2 units?

 

Thanks.

 

Nick.

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