mathspassion Posted December 23, 2016 Posted December 23, 2016 Today we will see how Piyush Goel discovered something while playing with numbers. Here is the story . One day while sitting idle, and having nothing important to do he was just scribbling on paper. he was writing random numbers and thinking how could link them. To his amazement he discovered this: he wrote down 0, 1, 2, 3, 4, 5. Next to each number he wrote their respective squares, viz. 0,1, 4, 9, 16, 25. Then start subtracting each successive square from the next bigger square. It looks something like this: (1-0), (4-1), (9-4), (16-9) and (25-16). What is the result? he got 1, 3, 5, 7, 9. Now again subtract each successive number from the next one in the order. We are performing this: (3-1), (5-3), (7-5) and (9-7). Surprisingly, he got (2, 2, 2, 2). A 2 in each case. he was amazed and decided to take a step further. This time with cubes. So here go my numbers 0, 1, 2, 3 ,4, 5, 6. And their respective cubes: 0, 1, 8, 27, 64, 125, 216. Time to perform first round of successive subtraction, i.e. (1-0), (8-1), (27-8), (64-27), (125-64) and (216-125). The result: 1, 7, 19, 37, 61, 91. Second round of successive subtraction as performed earlier: (7-1), (19-7), (37-19), (61-37) and (91-61). And this is what he got: 6, 12, 18, 24, 30. Successive subtraction performed the third time: (12-6), (18-12), (24-18) and (30-24). And this time he got the result (6, 6, 6, 6). You see, squaring means ‘to the power 2’ and he got the result 2 after 2 successive subtractions, which is the value of 2! Cubing means ‘to the power 3’ and after performing 3 successive subtraction he got 6 in each case which is nothing but the value of 3! He similarly performed with 4th and 5th powers of the first few whole numbers. He was surprised to find the final value of 24 and 120 which are of course the values of 4! and 5!. It was all right up to 5, but he wanted to go a notch higher and check for 6 just for my personal satisfaction. While doing for 6th power the calculations were massive and numbers so huge that it took him a couple of hours to do his calculations. Just to be sure he also did it for numbers upto 15. Put 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 and 15 and their respective 6th powers: 0,1,64,729, 4096, 15625, 46356, 11649, 262144, 531441, 1000000, 1771561, 2985984,4826809, 7829536 and 11390625. He kept on doing successive subtractions till to his contentment he finally got 720 for all which is the value of 6! With little efforts, we can work out algebraic relationship for the above but leave it for some other time.
Sriman Dutta Posted December 23, 2016 Posted December 23, 2016 Yes, I did so once too. Here's the explanation. For powers of two, [math] [(a+2)^2 - (a+1)^2]-[(a+1)^2 - a^2]=[a^2+4+4a-a^2-1-2a]-[a^2+1+2a-a^2]=[3+2a]-[1+2a]=3+2a-1-2a=2[/math]
mathspassion Posted December 23, 2016 Author Posted December 23, 2016 as the work done in digits upto 6 power like that you did ............................wow gr8 in the form of equations everyone says i have done.....................
Sriman Dutta Posted December 23, 2016 Posted December 23, 2016 (edited) After a bit of rough working, I get that to do this to powers of n, you need to open n brackets. On doing so and simplifying the equations, the terms of [math] a^n, a^{n-1}, a^{n-2},....[/math] cancel out leaving behind n! (which is also the numerator of the binomial coefficient). Edited December 23, 2016 by Sriman Dutta
mathspassion Posted December 24, 2016 Author Posted December 24, 2016 never say rough working everthing has own existence whatever we do never go waste it reacts......it,s one own choice who play with numbers others with n power ........................
Sriman Dutta Posted December 24, 2016 Posted December 24, 2016 By rough working, I meant that I worked only upto powers of 4 and then generalized the stuff.
mathspassion Posted December 24, 2016 Author Posted December 24, 2016 ok you know how difficult upto the power 6 for this .................as per figure 16 lines shows how much work done by....... some more work still pending ........pl wait......
AshBox Posted December 27, 2016 Posted December 27, 2016 Excellent work is done by you. Calculations become easy after this technique. Generally, I use online tools to work on maths related problems. But this seems quite interesting & useful to all.
mathspassion Posted January 2, 2017 Author Posted January 2, 2017 thnxs Happy New Year 2017 to all my math lovers.......
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