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Posted

I am currently reading a book on calculus and I have come across a problem which I can't solve. I do feel like the answer is something simple. Please note that I am fairly new to calculus.

 

post-123106-0-88619400-1483295327.png

 

Thank you.

Posted (edited)

What is your definition of f'(x) ?

 

Are you sure the question does not say

 

If f(x) is differentiable at xo then prove that.....etc ?

 

Consider the differentiability of f(x) = |x| and of f(x) =x2 at xo = 0

 

 

 

Edited by studiot
Posted

What is your definition of f'(x) ?

 

Are you sure the question does not say

 

If f(x) is differentiable at xo then prove that.....etc ?

 

Consider f(x) = |x| at xo = 0

 

I've lost all my maths skills (except for statistics), but we always denoted the derivative function of f(x) as f'(x).

Posted

 

I've lost all my maths skills (except for statistics), but we always denoted the derivative function of f(x) as f'(x).

 

Yes, that's right the derived function is f'(x).

Posted (edited)

I am currently reading a book on calculus and I have come across a problem which I can't solve. I do feel like the answer is something simple. Please note that I am fairly new to calculus.

 

attachicon.gifmathz.PNG

 

Thank you.

[latex]\frac{f(x_0+\Delta x)-f(x_0-\Delta x)}{2 \Delta x}=\frac{f(x_0+\Delta x)-f(x_0)+f(x_0)-f(x_0-\Delta x)}{2 \Delta x}[/latex]

 

"mathematic" beat me to it

Edited by zztop
Posted (edited)

[latex]\frac{f(x_0+\Delta x)-f(x_0-\Delta x)}{2 \Delta x}=\frac{f(x_0+\Delta x)-f(x_0)+f(x_0)-f(x_0-\Delta x)}{2 \Delta x}[/latex]

 

"mathematic" beat me to it

Thank you, this really helped me.

Edited by bahozkaleez

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