Proof Using Congruent Triangles

[NSX]

Can someone check over my proof please?

Thanks.

I'm using the delta symbol to signify triangle

 

Question: S is the midpoint of side QR of :delta: PQR. QT & RW are drawn perpendicular to PS or PS extended. Prove that QT=RW:

 

Here's my sol'n:

 

In :delta: QTS & :delta: RWS:

1. QS = RS (given)

2. Angle QTS = Angle RWS (given)

3. Angle TSQ = Angle WSR (Opp. Angle Theorem)

4. Therefore :delta: QTS :cong: :delta: RWS (Angle Angle Side) (State1, S2, S3)

5. Therefore QT=RW

 

Thanks. It's for a hw presentation for Monday.

 

I've attached a jpeg of what the question looks like:

[NSX]

whhops, or maybe it should go in the HW help part

[Dave]

Looks okay. Bit of a crap question though

[NSX]

Originally posted by dave

Looks okay. Bit of a crap question though

Well, that's what Grade12 Geometry & Discrete Math is like in Toronto...