studentteacher Posted February 11, 2017 Posted February 11, 2017 You travel 3 m north in 1s, and 4 m east 2 s. Displacement: 5 m in 3s. Average veolcity is 5/3 m/s. or V north = 3 m/s, and v east = 2 m/s. Average velocity for trip is (allegedly) 3.6 m/s. Obviously this wrong, but conceptually I'm not quite sure how to explain why it doesn't work.
swansont Posted February 11, 2017 Posted February 11, 2017 You travel 3 m north in 1s, and 4 m east 2 s. Displacement: 5 m in 3s. Average veolcity is 5/3 m/s. or V north = 3 m/s, and v east = 2 m/s. Average velocity for trip is (allegedly) 3.6 m/s. Obviously this wrong, but conceptually I'm not quite sure how to explain why it doesn't work. For the latter, the duration of the trips is not the same.
DrKrettin Posted February 12, 2017 Posted February 12, 2017 For a start, you must distinguish between speed and velocity. Velocity is a vector and has one component of speed and the other of direction. Speed is just a scalar quantity. Are you asking about average speed (easy) or average velocity (not quite so easy)?
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