Guest desifabalus Posted May 23, 2005 Posted May 23, 2005 Consider the following reaction: 4NH3 (g) +7O2 (g) <-->2N2O4 (g) + 6H2O (g) If the initial concentrations of N2O4 and H2O are 3.60 M. At equilibrium the concentration of H2O is 0.60 M. Calculate the equilibrium concentration of N2O4. Can someone tell me how to solve this, i am lost, thanks!
Bluenoise Posted May 24, 2005 Posted May 24, 2005 If the initial concentrations of N2O4 and H2[/size']O are 3.60 M. Are they both 3.60 M? Or are they combined 3.60 M? Anyways in the instance that they're both 3.60 Well you need 3.00 M of H2O to react to reach equilibrium, these require 1/3 as many of N2O4, so you have 1.00 M of N2O4 reacting. Which leaves you with 2.60 M N2O4 remaining.
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