Maxi Posted April 26, 2017 Posted April 26, 2017 Hi, According to the USP <643> I need to prepare a solution of 0.75 mg/mL of 1,4-Benzoquinone USP Reference Standard in order to get 0.5 mg/L or carbon (500 ppb). Could anyone please explain how the calculation is done? How do I know that I have to weigh in 0.75 mg of Benzoquinone and dilute in 1L of Water in order to get 500 ppb of carbon content? Thanks for your help!
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