LogSin Posted May 18, 2017 Share Posted May 18, 2017 (edited) In RE: https://www.google.com/patents/US20060145019?pageId=111028569981762970673&pageId=107422565180807765757 SUMMARY: This invention is a spacecraft with a triangular hull having charged flat plates on the vertical corners of the three sides. The two rear corners are charged to a potential V. The forward corner is charged to a potential −V. The 60° angle on the corner creates a line charge density singularity that produces a huge horizontal electric field pointing from the back to the front of the craft which is also parallel to the sides of the triangle. An array of horizontal slot antennas located on the sides of the triangular hull produce an electromagnetic wave with the electric field polarized in the vertical direction. This combination of fields produces a spacetime force in both the vertical and horizontal directions such that the spacecraft receives a lift force and a force of propulsion. Figure 1: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00001.png Figure 2: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00002.png Figure 3: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00003.png Figure 4: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00004.png Figure 5: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00005.png Figure 6: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00006.png Figure 7: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00007.png This invention is a spacecraft having a triangular hull with vertical electrostatic line charges on each corner. The line charges create a horizontal electric field that, together with a plane wave emitted by antennas on the side of the hull, generates a force per volume providing a unique combination of both lift and propulsion. Anyone want to put in some time on going through the math here? This is..unprecedented. The equations in the patent are quite interesting. Edited May 19, 2017 by LogSin Link to comment Share on other sites More sharing options...
Strange Posted May 18, 2017 Share Posted May 18, 2017 I would just point out that the invention is not in the public domain. Published != public domain. Link to comment Share on other sites More sharing options...
KipIngram Posted May 18, 2017 Share Posted May 18, 2017 I can't find it on uspto.gov. Link to comment Share on other sites More sharing options...
Raider5678 Posted May 19, 2017 Share Posted May 19, 2017 (edited) In RE: https://www.google.com/patents/US20060145019?pageId=111028569981762970673&pageId=107422565180807765757 SUMMARY: This invention is a spacecraft with a triangular hull having charged flat plates on the vertical corners of the three sides. The two rear corners are charged to a potential V. The forward corner is charged to a potential −V. The 60° angle on the corner creates a line charge density singularity that produces a huge horizontal electric field pointing from the back to the front of the craft which is also parallel to the sides of the triangle. An array of horizontal slot antennas located on the sides of the triangular hull produce an electromagnetic wave with the electric field polarized in the vertical direction. This combination of fields produces a spacetime force in both the vertical and horizontal directions such that the spacecraft receives a lift force and a force of propulsion. Figure 1: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00001.png Figure 2: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00002.png Figure 3: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00003.png Figure 4: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00004.png Figure 5: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00005.png Figure 6: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00006.png Figure 7: https://patentimages.storage.googleapis.com/US20060145019A1/US20060145019A1-20060706-D00007.png This invention is a spacecraft having a triangular hull with vertical electrostatic line charges on each corner. The line charges create a horizontal electric field that, together with a plane wave emitted by antennas on the side of the hull, generates a force per volume providing a unique combination of both lift and propulsion. Anyone want to put in some time on going through the math here? This is..unprecedented. The equations in the patent are quite interesting. So basically, an extremely short rail gun? Or, extremely fast. Edited May 19, 2017 by Raider5678 Link to comment Share on other sites More sharing options...
Mordred Posted May 19, 2017 Share Posted May 19, 2017 (edited) Not that I believe this will work, but the math you have on the first link is incredibly difficult to follow. Can you post the math here as the site gives me garbage characters. speaking of math why do you have only [latex]T_\mu[/latex] Did you forget the full tensor form? Ok there is too many obvious mistakes that it is obvious you don't know how the stress tensor works. [latex]T^{xx}, T^{yy},T^{zz}[/latex] is not part of the stress tensor coordinates. Secondly you specify polar coordinates but your ds^2 line element is in cartesian coordinates.( Though you did note they are Cartesian) however we need to see how your fields effect the Polar coordinates for curvature. I can't even begin to read your Poisson notation. Where is your Div and curl elements. Where is the corresponding Maxwell equations? What did you do slap formulas together without deriving them to make it sound like you did the calculations ? The (I would guess Japanese characters on the formulas) Means literally nothing to me. Please post the formulas here to avoid the confusing notations on your site. edit Found some of the Maxwell equations and I can only hazard a guess your japanese characters are to denote a matrix. Please confirm. Looking over this it won't work, from what I can see the polarity differences of the electromagnetic field on your three point on image 6 is still of positive density. I would suggest you calculate the effective action. The charge directions are not uni directional between magnetic poles but bidirectional. Ie positive to negative and negative to positive simultaneously. In essence positive charge in one direction with negative charge in the opposite direction. Yet both charges are still positive energy density. Just a side note assuming you could generate enough power to generate thrust your magnetic polarity alignment will literally tear your craft apart as the plates will try to seperate. Ever try to stick two magnets together in the same polarity alignments? There is a very easy experiment to prove I'm correct take a v shaped ferrous material and apply an two + and 1 negative charge at either end in your arrangement. Remove from the area any possible electromagnetic attractors. Place said experiment on a sheet of ice. Guaranteed you Will have no forward thrust as you effectively have a single magnetic. Edited May 19, 2017 by Mordred Link to comment Share on other sites More sharing options...
LogSin Posted May 19, 2017 Author Share Posted May 19, 2017 (edited) I can't find it on uspto.gov. http://appft.uspto.gov/netacgi/nph-Parser?Sect1=PTO1&Sect2=HITOFF&d=PG01&p=1&u=%2Fnetahtml%2FPTO%2Fsrchnum.html&r=1&f=G&l=50&s1=%2220060145019%22.PGNR.&OS=DN/20060145019&RS=DN/20060145019 Not that I believe this will work, but the math you have on the first link is incredibly difficult to follow. Can you post the math here as the site gives me garbage characters. speaking of math why do you have only [latex]T_\mu[/latex] Did you forget the full tensor form? Ok there is too many obvious mistakes that it is obvious you don't know how the stress tensor works. [latex]T^{xx}, T^{yy},T^{zz}[/latex] is not part of the stress tensor coordinates. Secondly you specify polar coordinates but your ds^2 line element is in cartesian coordinates.( Though you did note they are Cartesian) however we need to see how your fields effect the Polar coordinates for curvature. I can't even begin to read your Poisson notation. Where is your Div and curl elements. Where is the corresponding Maxwell equations? What did you do slap formulas together without deriving them to make it sound like you did the calculations ? The (I would guess Japanese characters on the formulas) Means literally nothing to me. Please post the formulas here to avoid the confusing notations on your site. edit Found some of the Maxwell equations and I can only hazard a guess your japanese characters are to denote a matrix. Please confirm. Looking over this it won't work, from what I can see the polarity differences of the electromagnetic field on your three point on image 6 is still of positive density. I would suggest you calculate the effective action. The charge directions are not uni directional between magnetic poles but bidirectional. Ie positive to negative and negative to positive simultaneously. In essence positive charge in one direction with negative charge in the opposite direction. Yet both charges are still positive energy density. Just a side note assuming you could generate enough power to generate thrust your magnetic polarity alignment will literally tear your craft apart as the plates will try to seperate. Ever try to stick two magnets together in the same polarity alignments? There is a very easy experiment to prove I'm correct take a v shaped ferrous material and apply an two + and 1 negative charge at either end in your arrangement. Remove from the area any possible electromagnetic attractors. Place said experiment on a sheet of ice. Guaranteed you Will have no forward thrust as you effectively have a single magnetic. Thank you so much for taking a look, I really want to know if this stuff would work. I implore you to review it more. Here are two links to the uspto website for this patent: text: http://appft.uspto.gov/netacgi/nph-Parser?Sect1=PTO1&Sect2=HITOFF&d=PG01&p=1&u=%2Fnetahtml%2FPTO%2Fsrchnum.html&r=1&f=G&l=50&s1=%2220060145019%22.PGNR.&OS=DN/20060145019&RS=DN/20060145019 images: http://pdfaiw.uspto.gov/.aiw?PageNum=0&docid=20060145019&IDKey=2A5F35FAC447&HomeUrl=http%3A%2F%2Fappft.uspto.gov%2Fnetacgi%2Fnph-Parser%3FSect1%3DPTO1%2526Sect2%3DHITOFF%2526d%3DPG01%2526p%3D1%2526u%3D%25252Fnetahtml%25252FPTO%25252Fsrchnum.html%2526r%3D1%2526f%3DG%2526l%3D50%2526s1%3D%25252220060145019%252522.PGNR.%2526OS%3DDN%2F20060145019%2526RS%3DDN%2F20060145019 (scroll to page 9 for equations) The matrices are in the 'images' link pages 9 to 11 You can zoom-in on the PDF to make the characters look clearer. Edited May 19, 2017 by LogSin Link to comment Share on other sites More sharing options...
Mordred Posted May 19, 2017 Share Posted May 19, 2017 (edited) Doesn't make any difference. This is a fairly easy problem set. Assign each charge then calculate the vector sum of each charge using Coulombs law. This is actually a standard practice problem taught in many textbooks. There are plenty of 3 charge examples on the net in a triangle. Don't stop at q1 also do q2 and q3. Your a rigid body so you have to calculate the sum of force on all 3. Also doesn't change the invalid coordinates on your stress tensor.... Though we don't even need to deal with the stress tensor to prove this won't work simply apply Coulombs law and Newtons 3 laws of inertia. If you do it right you will find the sum of forces is zero at the centre of your triangle and the sum of force will be a function of radius from that centre point regardless of the charge values. Edited May 19, 2017 by Mordred Link to comment Share on other sites More sharing options...
LogSin Posted May 19, 2017 Author Share Posted May 19, 2017 (edited) Would that still apply if there was a device that could produce a potential energy ellipsoidal bubble that creates an electric dipole moment? Rotating to make magnetic moment and a magnetic field gradient in the vertical direction that produces a lift force? Use of a magnetic vortex generator to bring in low density hyperspace energy in order to increase the field strengths? Edited May 19, 2017 by LogSin Link to comment Share on other sites More sharing options...
Mordred Posted May 19, 2017 Share Posted May 19, 2017 (edited) Can you name such a device? A negative vortex generator must apply negative mass. Do you know any way without some undiscovered exotic material to generate negative mass? This is the problem with the Alcubierre drive Edited May 19, 2017 by Mordred Link to comment Share on other sites More sharing options...
LogSin Posted May 19, 2017 Author Share Posted May 19, 2017 (edited) Can you name such a device? https://www.google.com/patents/US20030209635 Do you know any way without some undiscovered exotic material to generate negative mass? This is the problem with the Alcubierre drive https://www.google.com/patents/US20030197093 all i got Edited May 19, 2017 by LogSin Link to comment Share on other sites More sharing options...
Mordred Posted May 19, 2017 Share Posted May 19, 2017 (edited) My point exactly if you dig deeper its also often applied in free energy patents etc. If we had such a device lol. Recall Newtons third law on your patent equal plus opposite reaction. If time allows this weekend (I'm a little busy) I'll run through and post the 3 charge triangle mathematics. Edited May 19, 2017 by Mordred Link to comment Share on other sites More sharing options...
LogSin Posted May 19, 2017 Author Share Posted May 19, 2017 (edited) My point exactly if you dig deeper its also often applied in free energy patents etc. If we had such a device lol. Recall Newtons third law on your patent equal plus opposite reaction. If time allows this weekend (I'm a little busy) I'll run through and post the 3 charge triangle mathematics. That would be great! & it's not my patent, although we do share a last name... Pretty sure this John St. Clair is a time traveler. The year.. 1912 patent? haha probably a coincidence https://www.google.com/patents/US1070075 granted, this guy has some pretty wacko stuff: 'a flat bifilar magnetic bucking field electrical coil, crystal ball, lever arm and frequency generator for producing a linear flow of hyperspace energy at right angles to a rotating flow of astral chakra energy.' heh. but then I come across some of his other stuff like this: https://www.google.com/patents/US20060072226 and at first you think 'wow what a loon' but then you see this: https://www.cia.gov/library/readingroom/docs/CIA-RDP96-00788R001900760001-9.pdf followed by those coordinates on Mars: http://imgur.com/jcH2MC9 and all of a sudden you're in a straight jacket. Edited May 19, 2017 by LogSin Link to comment Share on other sites More sharing options...
Mordred Posted May 19, 2017 Share Posted May 19, 2017 Well I'm extremely glad you didn't waste any money on this patent. Patent offices do not care if the device works or not lol. Link to comment Share on other sites More sharing options...
Bender Posted May 19, 2017 Share Posted May 19, 2017 The math is really very simple: [math]F_1=-F_2[/math] Repeat for every force the spacecraft exerts on itself [math]\Sigma F=0[/math] in other words: no thrust. Technically, sending out electromagnetic waves gives a tiny bit of thrust because of its tiny momentum, but you'd be better off just sending the waves backwards. Link to comment Share on other sites More sharing options...
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