Sarahisme Posted June 13, 2005 Share Posted June 13, 2005 hey another questions guys.... isnt there one too many Hydrogens on the left most carbon atom (to the right of the arrow)?? Link to comment Share on other sites More sharing options...
budullewraagh Posted June 13, 2005 Share Posted June 13, 2005 nope. it's a methyl group singly bonded to a carbon. 3+1=4 Link to comment Share on other sites More sharing options...
Sarahisme Posted June 13, 2005 Author Share Posted June 13, 2005 hmmm then i don't see how this mechnism reaction works.... does that OH coming in take that hydrogen away? Link to comment Share on other sites More sharing options...
Sarahisme Posted June 13, 2005 Author Share Posted June 13, 2005 also just a second quick question.... shouldnt the N on the right side of the arrow have a postive charge (+) on it? Link to comment Share on other sites More sharing options...
BenSon Posted June 13, 2005 Share Posted June 13, 2005 No its got a neutral charge 3-0-3=0 ~Scott Link to comment Share on other sites More sharing options...
Sarahisme Posted June 13, 2005 Author Share Posted June 13, 2005 right ok, cool so would you be able to quickly explain (if you have time) how the first one works (in the initial post of this thread)?? Link to comment Share on other sites More sharing options...
Sarahisme Posted June 13, 2005 Author Share Posted June 13, 2005 oh and whats with the "3-0-3=0"?? Link to comment Share on other sites More sharing options...
BenSon Posted June 13, 2005 Share Posted June 13, 2005 so would you be able to quickly explain (if you have time) how the first one works (in the initial post of this thread)?? Tell you the truth this stuff is abit beyond me but I think you are right either one of the hydrogens on the first carbon should be removed or it should be carrying a negative charge. oh and whats with the "3-0-3=0"?? Formal charge ~Scott Link to comment Share on other sites More sharing options...
Sarahisme Posted June 13, 2005 Author Share Posted June 13, 2005 k, thanks BenSon Link to comment Share on other sites More sharing options...
Bluenoise Posted June 13, 2005 Share Posted June 13, 2005 The first one is wrong. They screwed up the mechanism. There should be one less hydrogen on the carbon. The hydroxyl subtracts the hydrogen to give water and a double bond forms stabalising the carbon. The oxygen is left with a negative charge. Yeah the question is messed up. Just count the number of hydrogens there is an imbalance. Link to comment Share on other sites More sharing options...
budullewraagh Posted June 13, 2005 Share Posted June 13, 2005 yes, in the overall reaction, there is an extra hydrogen atom in the product. in the product, the carbon on the left should be bonded to two hydrogen. the third joins the hydroxyl radical Link to comment Share on other sites More sharing options...
Bluenoise Posted June 13, 2005 Share Posted June 13, 2005 also just a second quick question.... shouldnt the N on the right side of the arrow have a postive charge (+) on it? if the hydrogen was to leave with the electrons yeah it would have a positive charge but this wouldn't happen. Just to clear it up but what would likely happen is the hydrogen would remain, the nitrogen would then have a positive formal charge. This hydrogen would then be acidic and could easily be lost leaving behind a lone pair. Link to comment Share on other sites More sharing options...
Sarahisme Posted June 14, 2005 Author Share Posted June 14, 2005 hmmm ok, yeah thats makes sense, thanks once again Link to comment Share on other sites More sharing options...
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