Sara Taboni Miller Posted August 26, 2017 Posted August 26, 2017 (edited) The space shuttle orbits 300 km above Earth surface , that has radius 6400 km . What is the gravitational acceleration experienced by the space shuttle ? Answer is 8.9 m/s^2 . I'm trying to equal mv ^2 / r = mMG/r^2 , where v^2/r is "a", so that I get a= mMG/r .. and I put r= 6400+300 but it isn't correct.. just a hint would be great , thank you in advance! Edited August 26, 2017 by Sara Taboni Miller
Endy0816 Posted August 26, 2017 Posted August 26, 2017 Think it requires: mg=(mMG)/r^2 and ma = (mMG)/(r+300)^2 not 100% sure though. Generally doesn't seem like you have enough knowns from only the information provided. 1
swansont Posted August 26, 2017 Posted August 26, 2017 You already have ma = GMm/r^2 M is the mass of the earth. You know the radius. G is a constant. 1
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