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Posted

Hi everyone, I just have a quick question that is blocking me with my studying, if I'm asked to know the order of readings on an ammeter in a circuit , and even more than one since there are several resistors , how an I suppose to know that? Even Smallest to largest .. :/  I really don't know how that work , but I'm aware that they are always connected in series . 

Thanks the attention ! 

Posted

There must be more to this question so post the actual question and preferably the circuit.

In particular what do they mean by order?

 

Polarity?

Connection with a voltmeter as well?

Position in circuit?

Posted

Is English language the problem?

 

I really don't understand what you were asking and it seems no one else was willing to hazard a guess either.

 

So please try again to explain your question.

Posted

I guess you are simply asking about ohms law V = I x R, Where V = volts, I = amps, and R = resistance.

If you have several resistors in series R1 to R5 for instance this can be rewritten V = I ( R1+R2+R3+R4+R5 ) It is the same current flowing through each resistor. The total voltage across the resistors is the sum of the voltage induced in the individual resistors. V = VR1 + VR2 + VR3 + VR4 + VR5.

I hope the above helps, what is your first language.

  • 2 weeks later...
Posted
On 8/28/2017 at 3:43 PM, Handy andy said:

I guess you are simply asking about ohms law V = I x R, Where V = volts, I = amps, and R = resistance.

If you have several resistors in series R1 to R5 for instance this can be rewritten V = I ( R1+R2+R3+R4+R5 ) It is the same current flowing through each resistor. The total voltage across the resistors is the sum of the voltage induced in the individual resistors. V = VR1 + VR2 + VR3 + VR4 + VR5.

I hope the above helps, what is your first language.

Italian :) thank you ! 

On 8/28/2017 at 3:22 PM, studiot said:

Is English language the problem?

 

I really don't understand what you were asking and it seems no one else was willing to hazard a guess either.

 

So please try again to explain your question.

Sorry I got it but I haven't been able to reply sooner ! Thanks ! 

 

  • 3 weeks later...

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