DimaMazin Posted August 28, 2017 Posted August 28, 2017 Circle is shared by infinite quantity of equal triangles. Sides a and b are radiuses of the circle. Side c is chord, At=1/4[(a+b+c)(-a+b+c)(a-b+c)(a+b-c)]1/2 At=1/4[(2r+c)(c)(c)(2r-c)]1/2 At=1/4[(4r2-c2)c2]1/2 At=1/4[4r2c2-c4]1/2 c=2Pi*r / infinity Ac= infinity*At Ac=(1/4)*infinity[4r24Pi2r2 / infinity2-16Pi4r4 / infinity4]1/2 Ac=1/4[16Pi2r4-16Pi4r4 / infinity2]1/2 Ac=Pi*r2 At is triangle area Acis circle area
John Cuthber Posted August 28, 2017 Posted August 28, 2017 Do you mean like thishttps://en.wikipedia.org/wiki/Area_of_a_circle#Rearrangement_proof
DimaMazin Posted August 29, 2017 Author Posted August 29, 2017 8 hours ago, John Cuthber said: Do you mean like thishttps://en.wikipedia.org/wiki/Area_of_a_circle#Rearrangement_proof What is similar of those?
Strange Posted August 29, 2017 Posted August 29, 2017 Your proof is not correct because it includes things like multiplying and dividing by infinity. It could probably be reworked in terms of limits to come up with a valid proof. 1
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