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Posted

Make L the subject of the equation for [math]\frac{1}{3}pK^{\frac{1}{3}L^{-\frac{2}{3}}}=w[/math].

 

My friend told me that the answer is [math]L=\left(\frac{p}{3w}\right)^\frac{3}{2}K^2[/math], but I got [math]L=\left(\frac{p}{3w}\right)^\frac{3}{2}K^\frac{1}{2}[/math].

 

Am I right or is my friend wrong?

 

_____________________

Kettheya Uong

Posted

I'm pretty sure you're right, but I think you made a typo with the latex. Is the equation as you stated, or is it:

 

[math]\tfrac{1}{3}pK^{\frac{1}{3}} L^{-\frac{2}{3}} = w[/math]?

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