ku Posted June 21, 2005 Posted June 21, 2005 Make L the subject of the equation for [math]\frac{1}{3}pK^{\frac{1}{3}L^{-\frac{2}{3}}}=w[/math]. My friend told me that the answer is [math]L=\left(\frac{p}{3w}\right)^\frac{3}{2}K^2[/math], but I got [math]L=\left(\frac{p}{3w}\right)^\frac{3}{2}K^\frac{1}{2}[/math]. Am I right or is my friend wrong? _____________________ Kettheya Uong
Dave Posted June 21, 2005 Posted June 21, 2005 I'm pretty sure you're right, but I think you made a typo with the latex. Is the equation as you stated, or is it: [math]\tfrac{1}{3}pK^{\frac{1}{3}} L^{-\frac{2}{3}} = w[/math]?
abeefaria Posted June 21, 2005 Posted June 21, 2005 I agree with Dave's answer if indeed, L is not part of the exponent.
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