Chu Posted October 12, 2017 Share Posted October 12, 2017 (edited) A chameleon can accelerate its tongue in order to catch an insect at an impressive rate of 500m/s^2. How quickly must a fly located at 5cm from the chameleon react if it is to escape? Given: Vi = 0 Vf = ? xi = 0 xf = 5 cm a = 500m/s^2 Using the equation: Vf2=Vi2+2a(xf-xi) Vf=70.71m/s Could someone please double check this answer for me. Thanks! Edited October 12, 2017 by Chu Link to comment Share on other sites More sharing options...
J.C.MacSwell Posted October 12, 2017 Share Posted October 12, 2017 does it seem reasonable? If that is the final velocity the average would be half that...around 35m/s...and it would have taken about a seventh of a second to get to 70.71m/s You might want to double check the decimal place of your result... Link to comment Share on other sites More sharing options...
Chu Posted October 12, 2017 Author Share Posted October 12, 2017 I see what I did wrong. I didn't do parenthesis first and went to multiplication. Link to comment Share on other sites More sharing options...
J.C.MacSwell Posted October 12, 2017 Share Posted October 12, 2017 4 minutes ago, Chu said: I see what I did wrong. I didn't do parenthesis first and went to multiplication. Not sure what you mean exactly. What was your result? Link to comment Share on other sites More sharing options...
swansont Posted October 12, 2017 Share Posted October 12, 2017 You also haven't answered the question. Link to comment Share on other sites More sharing options...
J.C.MacSwell Posted October 12, 2017 Share Posted October 12, 2017 Really only enough information to answer "time required to react before getting eaten" Link to comment Share on other sites More sharing options...
Chu Posted October 21, 2017 Author Share Posted October 21, 2017 I was using the wrong equation! using Xf=1/2at2 0.05=1/2(500)*t2 0.05=250*t2 t2=0.0002 square this to get: t=0.014 s Link to comment Share on other sites More sharing options...
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