Externet Posted June 25, 2005 Posted June 25, 2005 Hi. To turn 1Kg of water at 20ºC into ice at -10ºC, is this calculation correct? : Cooling the water 20ºC = 20 x 1KCal = 20 KCal Freezing 1 Kg = 80 KCal Cooling ice 10ºC = 10 x 500 Cal = 5 KCal Total = 105 KCalories must be extracted. How to calculate the same under 50 mm Hg vacuum ? Miguel
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