reerer Posted October 30, 2017 Share Posted October 30, 2017 § 1. Maxwell's Structure of Light The electromagnetic transverse wave equations of light are derived using Maxwell's equations, ∇ x E = - dB/dt........................∇ x B = 1/c (dE/dt).....................................73a,b Maxwell's curl equations (equ 73a,b) are expanded to form, dEz/dy - dEy/dz = - dBx/dt...........................................................................74 dEx/dz - dEz/dx = - dBy/dt...........................................................................75 dEy/dx - dEx/dy = - dBz/dt...........................................................................76 ........................................................... dBz/dy - dBy/dz = 1/c (dEx/dt)....................................................................77 dBx/dz - dBz/dx = 1/c (dEy/dt)....................................................................78 dBy/dx - dBx/dy = 1/c (dEz/dt)..................................................... ..............79 The z-direction electric transverse wave equations is derived using equations 74 and 78 by eliminating dEy/dz and dBz/dx to form (Jenkins, p. 410), dEy/dz = 1/c (dBx/dt)..............................dBx/dz = 1/c (dEy/dt)...................80a,b Differentiating equation 80a, with the respect to d/dz, and equation 80b with respect to d/dt produces (Condon, p, 1-108), d2Ey/d2z = 1/c (d2Bx/dtdz)......................d2Bx/dtdz = 1/c (d2Ey/d2t)...........81a,b Equating equations 81a,b, d2Ey/d2z = 1/c2 (d2Ey/d2t)...........................................................................82 Differentiating equation 82a, with the respect to d/dt, and equation 82b with respect to d/dz produces , d2Ey/dtdz = 1/c (d2Bx/d2t)......................d2Bx/d2z = 1/c (d2Ey/dtdz)...........83a,b Equating equations 83a,b forms, d2Bx/d2z = 1/c2 (d2Bx/d2t)..........................................................................84 Equations 82 and 84 are used to derive the z direction electromagnetic transverse wave equations of light (fig 17), Ey = Eo cos(kz - wt) ĵ ..............................................................................85 Bx = Bo cos(kz -wt) î ................................................................................86 In the derivation of equations 80a,b, 14 of the 18 differential components that constitute Maxwell's equations are eliminated since an electromagnetic field within a volume forms a horizontal wave. What do you think of the mathematic that is being depicted? Link to comment Share on other sites More sharing options...
Vmedvil Posted November 15, 2017 Share Posted November 15, 2017 (edited) Um, Elimination doesn't work on differential equations, they are arrays unless you mean elimination in the array or matrix form to solve them. Wait, I get what he is saying, but he gave it the wrong term. Edited November 15, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
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