Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 (edited) 36 minutes ago, studiot said: Yes in the linear case there need be no acceleration. In the rotating case you cant do without it. No, the Radius term is just missing in pC being 1 for E = MC2 + pC Which would be the radius from the observer frame R or l, which is 1 in linear but in angular is not always 1. Which does require an acceleration to do, but is not the reason why. Edited November 27, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
swansont Posted November 27, 2017 Share Posted November 27, 2017 1 hour ago, Vmedvil said: Is it really different besides being over a radius? Yes, it is really different. Were you to actually try and apply the concepts in solving physics problems, it would become obvious. 48 minutes ago, Vmedvil said: E = MC2 + pC That's not a valid equation. Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 (edited) 7 minutes ago, swansont said: Yes, it is really different. Were you to actually try and apply the concepts in solving physics problems, it would become obvious. I'll take that bet calculate for Linear Momentum E1 = MC2 + PC , where R = 1, then do the same for angular momentum and see if it is different when E2 = MC2 + PC , P = RL , L = Iω , I = MR2 you will find E1 = E2 Edited November 27, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
swansont Posted November 27, 2017 Share Posted November 27, 2017 3 minutes ago, Vmedvil said: I'll take that bet calculate for Linear Momentum E1 = MC2 + PC , where R = 1, then do the same for angular momentum and see if it is different when E2 = MC2 + PC , P = RL , you will find E1 = E2 E = MC2 + PC is not a valid equation (i.e. it does not hold true in general), and of what value would an equation be that's only valid for R=1? Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 (edited) 4 minutes ago, swansont said: E = MC2 + PC is not a valid equation (i.e. it does not hold true in general), and of what value would an equation be that's only valid for R=1? I just rooted the entire equation to not have to type all the exponents E2 = M2C4 + p2C2 either way. Edited November 27, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
swansont Posted November 27, 2017 Share Posted November 27, 2017 Just now, Vmedvil said: I just rooted the E2 = M2C4 + P2C2 Then you did it incorrectly. (MC2 + PC)2 ≠ M2C4 + P2C2 i.e. there is a missing cross-term of 2MPC2 Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 (edited) 35 minutes ago, swansont said: Then you did it incorrectly. (MC2 + PC)2 ≠ M2C4 + P2C2 i.e. there is a missing cross-term of 2MPC2 Damn it, I don't care which way you do it, it will be the same as long as R = 1 on Angular, but yes I typed that quickly but it does not (MC2 + PC)2 ≠ M2C4 + P2C2 Edited November 27, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
studiot Posted November 27, 2017 Share Posted November 27, 2017 Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 (edited) 13 minutes ago, studiot said: It happens when addressing multiple threads at once constantly hearing PING PING PING PING, Medvil does severe multiforuming and tasking, but yes use E2 = M2C4 + P2C2 or your answer will be wrong, but it would not matter as both sides were by the same amount wrong so it would be right for the E1 = E2 scenario either way. Edited November 27, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
swansont Posted November 27, 2017 Share Posted November 27, 2017 1 hour ago, Vmedvil said: It happens when addressing multiple threads at once constantly hearing PING PING PING PING, Medvil does severe multiforuming and tasking, but yes use E2 = M2C4 + P2C2 or your answer will be wrong, but it would not matter as both sides were by the same amount wrong so it would be right for the E1 = E2 scenario either way. It will actually matter a great deal. Is R 1 meter, or 1 cm, or 1 foot? (which only begins to illuminate why the claim doesn't work) Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 2 minutes ago, swansont said: It will actually matter a great deal. Is R 1 meter, or 1 cm, or 1 foot? (which only begins to illuminate why the claim doesn't work) Meters obvious but just use the correct form. Link to comment Share on other sites More sharing options...
swansont Posted November 27, 2017 Share Posted November 27, 2017 2 minutes ago, Vmedvil said: Meters obvious but just use the correct form. It's not obvious. If it only works in one unit system then it's a happy accident, and not something that's universally true. Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 6 minutes ago, swansont said: It's not obvious. If it only works in one unit system then it's a happy accident, and not something that's universally true. Well, for that E2 = M2C4 + p2C2 It only works at one point but for other kinematics equations universally true. Link to comment Share on other sites More sharing options...
swansont Posted November 27, 2017 Share Posted November 27, 2017 2 hours ago, Vmedvil said: Well, for that E2 = M2C4 + p2C2 It only works at one point but for other kinematics equations universally true. Prove it. Link to comment Share on other sites More sharing options...
Vmedvil Posted November 27, 2017 Share Posted November 27, 2017 (edited) 20 minutes ago, swansont said: Prove it. MV = p , p = R x L, L = I ω , I = MR2 , ω = V/R Edited November 27, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
swansont Posted November 28, 2017 Share Posted November 28, 2017 15 hours ago, Vmedvil said: MV = p , p = R x L, L = I ω , I = MR2 , ω = V/R and? Link to comment Share on other sites More sharing options...
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