Sciencegeeknm Posted February 6, 2018 Posted February 6, 2018 On the attached file I have tried to work out the reaction pathway. The reaction given at the top is from a chemistry lecture I watched but no mechanism was given. In the first mechanism I just reacted one of the N20 molecules with hydroxide. The hydroxide attaching to the Nitrogen and is then deprotenated by the second OH- I now have H20 and N03- but it doesn't explain how the second N20 molecule ends up with a second electron on the Nitrogen. In the second mechanism (which I think is correct) the 2 N20 molecules join together to form the dimer N2O4. OH- attacks the anti bonding orbital of the Positive Nitrogen and the 2 electrons from the N-N bond go onto the other N20 molecule. The OH attached is now deprotenated by the second OH- to leave H20,N03- and of course a lone pair on the Nitrogen. It would be great if someone could verify the second mechanism as correct . Regards Nick
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now