Nor Antonio Posted February 16, 2018 Posted February 16, 2018 (edited) Hi, can you help me solve this monohybrid cross? (Most especially on letter B). Thank you. 1. In humans, achondroplasia “dwarfism” is dominant over normal. A homozygous dominant person dies before the age of one. A heterozygous person is dwarfed. A homozygous recessive individual is normal. A heterozygous dwarf man marries a dwarf heterozygous woman. a. What is the probability (in percent) of a having a normal child? b. What is the probability (in percent) that the next child will also be normal? c. What is the probability (in percent) of having a child that is a dwarf? d. What is the probability (in percent) of having a child that dies at one from this disorder? Edited February 16, 2018 by Nor Antonio Wrong spelling
StringJunky Posted February 16, 2018 Posted February 16, 2018 (edited) Look at the possible combinations N = Normal height and A -Achondroplastic : Man A and N Woman A and N A x A = Achondroplastic and won't survive A x N = Achondroplastic N x A =Achondroplastic N x N = Normal Express the frequency of each type as a % .of the total crosses. Edited February 16, 2018 by StringJunky
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