nancy9494 Posted February 26, 2018 Posted February 26, 2018 (edited) So i think this is a hydrolysis of an ester, but I'm not sure. If it is, do I need to add water as a solvent? Most of the examples I have seen with an ester under basic conditions is that there is H2O written alongside the anionic base. Thanks in advance Edited February 26, 2018 by nancy9494 forgot picture
hypervalent_iodine Posted February 26, 2018 Posted February 26, 2018 I think you need to start by counting your carbons. They don't look like they match between your reagent / reactant and your product. You might also like to consider the feasibility of your sulfur reagent. 1
BabcockHall Posted February 27, 2018 Posted February 27, 2018 @OP, If you have a sodium as a countering, what does that suggest about the rest of the reagent?
STEPHANIECT Posted February 2 Posted February 2 If you are doing ester hydrolysis under basic conditions, you would need water to finish the reaction. Water can be added directly or be part of the solvent system.
chenbeier Posted February 2 Posted February 2 (edited) I think there is an error . CH3SO2 is wrong. It is sodium and Dimethylsulfon (CH3)2SO2 as reactant this forms the CH active sodium salt CH3SO2CH2- + Na+. This will attack the Ester and the Methanolate will be pushed out. No water involved. RCO-OCH3 + CH3SO2CH2- => RCO-CH2SO2CH3 + CH3O- This will be neutralised with mild acid. Edited February 2 by chenbeier
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