Need confirmation on the weight of this sphere.

[Jason Summer]

So here's a clip from The legend of Zelda: Twilight princess

How heavy is the goron being thrown, assuming His weight is average rock density, and the radius of his curled up form is approximately 8ft.

I tried multiple time to use the sphere volume formula to figure it out, but my latest attempt yielded only 380 lbs. That can't be right.

Also, it might be fun to calculate the forces being applied to links body during the throw, once we know how much he's throwing.

[Strange]

density of rock: 2650 kg/m³  (https://www.wolframalpha.com/input/?i=density+of+rock)

volume of sphere radius 8 feet: 2144.66 ft³ (https://www.wolframalpha.com/input/?i=volume+of+sphere+radius+8+feet)

2650 kg/m³  * 2144.66 feet³ = 354,800 lb (https://www.wolframalpha.com/input/?i=2650+kg%2Fm^3  * 2144.66+ft^3+in+pounds)

[Jason Summer]

Sorry, I meant to say that the diameter was 8 feet, not radius, so 177,400lbs. He threw the Goron about 4 times it's length, so 32ft/0.98 seconds. 80,400kg × 10.5 m/s= 844,200 newtons of force on links body?

[swansont]

No, you wouldn't divide by 2. The volume depends on r^3, so if r is halved, the weight is reduced by a factor of 8, so 44,350 lbs.

[Jason Summer]

Also I noticed that strange used a mixture of metric and imperial units, which I think would mess up the formula. I am fairly certain that the formula is based on the metric system, as most scientific formulas are. It is rather troublesome being raised with the imperial system. I still haven't the slightest idea the length of a kilometer, or the weight of a kilogram, or even the difference of 1 degree Celsius.

Edited April 19, 2018 by Jason Summer

[Strange]

1 hour ago, Jason Summer said:

Also I noticed that strange used a mixture of metric and imperial units, which I think would mess up the formula.

I would normally start off by converting your 8 feet into metres and calculate it from there. But as I was getting Wolfram to do all the calculation, I didn't bother. It doesn't matter what units you use, as long as you convert them all to the same thing at some point. The equation is the same for feet or metres.