Is it possible to find all consecutive prime in fix range ? .

[satwnz]

Prime ={NPn*±IPn } i.e  30N±I5,

Prime Number range 5<=P<25, 

I5 have 2 AP series with  C.D=6,  and first element = 5 & 7

5,11,17,23….infinite, C.D=6, T1=5

7,13,19,25…..infinite, C.D=6, T1=7

in example below you can see with help of I5 AP series we can find all Prime Number range 5<=P<25

P5*	I5	I5	Prime=(P5*-I5)	Prime=       (I5-P5*)
30	25	35	5	5
30	23	37	7	7
30	19	41	11	11
30	17	43	13	13
30	13	47	17	17
30	11	49	19	19
30	7	53	23	23
60	55	65	5	5
60	53	67	7	7
60	49	71	11	11
60	47	73	13	13
60	43	77	17	17
60	41	79	19	19
60	37	83	23	23

[studiot]

Your headline question

Quote

Is it possible to find all consecutive prime in fix range ? .

 

If you define a range as having two endpoints,

In theory, yes by the method of exhaustion.

 

But what does this have to do with your first post?

[satwnz]

Bcz  we can find out any consecutive prime number by just subtraction of two numbers of series i.e Pn*, and Ipn.

Ipn series	Number  of series	Commonn Diffrance	Prime number  in range	Remarks
I2	1	2	2 TO 4	Series in AP
I3	1	6	3 TO 9	Series in AP
I5	2	30	5 TO 25	Series in AP, and Got prime by subtarction  30*N-I5  where N is natural no
I7	8	210	7 TO 49	Series in AP, and Got prime by subtarction 210*N-I7  where N is natural no
I11	48	2310	11 TO 121	Series in AP, and Got prime by subtarction  2310*N-I11  where N is natural no
I13	480	30030	13 TO 169	Series in AP, and Got prime by subtarction  30030*N-I13  where N is natural no
I17	5760	510510	17 TO 289	Series in AP, and Got prime by subtarction 510510*N-I17  where N is natural no
I19	92160	9699690	19 TO 361	Series in AP, and Got prime by subtarction  9699690*N-I19  where N is natural no
I23	1658880	223092870	23 TO 529	Series in AP, and Got prime by subtarction  223092870*N-I23  where N is natural no
I29	36495360	6469693230	29 TO 841	Series in AP, and Got prime by subtarction  6469693230*N-I29  where N is natural no
I31	1021870080	200560490130	31 TO 961	Series in AP, and Got prime by subtarction  200560490130*N-I31  where N is natural no
I37	30656102400	7420738134810	37 TO 1369	Series in AP, and Got prime by subtarction  7420738134810*N-I37  where N is natural no
I41	1103619686400	304250263527210	41 TO 1681	Series in AP, and Got prime by subtarction  304250263527210*N-I41  where N is natural no
.	.	.	.	.
.	.	.	.	.
.	.	.	.	.
Ipn	(p1-1)*(p2-1)*(p3-1)*(p4-1)*………….(pn-1)=k		Pn  To Pn^2	Series in AP, and Got prime by subtarction  {NPn*±IPn }

 

 

 

[studiot]

1 hour ago, satwnz said:

Bcz  we can find out any consecutive prime number by just subtraction of two numbers of series i.e Pn*, and Ipn.

So what?

Was that non-English supposed to be an answer?

If you put a little more effort into discussion and a lot less effort into typing out endless lists of numbers perhaps someone else might also be prepared to discuss with you.

 

[Strange]

21 hours ago, satwnz said:

I5 have 2 AP series with  C.D=6

What is I5?

What is AP?

What is C.D?

21 hours ago, satwnz said:

T1=5

What is T1?

3 hours ago, satwnz said:

Ipn series  Number  of series

What is "Ipn series"? And how is it calculated?

What is "Number of series"? And how is it calculated?

 

You are not explaining yourself well. Try a few proper sentences. Try a spell. checker. Try explaining what all your abbreviations mean.