jlcowgill Posted July 16, 2005 Posted July 16, 2005 questions is find the interval of increasing and decreasing H(x) = (x^2-1)^3 H'(x) = 6x(x^2 - 1)^2 is my crital numbers x = 0, x= sq root 1, x= sq root of -1 when i am plugging them in numbers i plug them in to the deritive example -2 it = a negitive number decreasing ,-.5 it is decreasing, .5 increasing , 2 increasing them for concave up or down i do the same thing and get H"(x) = 12x(x^2-1) are these concepts correct? thanks joe
Pat Says Posted July 16, 2005 Posted July 16, 2005 If your first derivative is negative then your equation's slope is negative; if your second derivative is negative then your equation is concave down and vice-versa. Do you know what a sign chart is? This will give you a good representation of how your equation will look when graphed. For all intents and purposes the critical points on the 1st derivative will mean the graph has a slope of zero or a vertical slope. For the 2nd derivative the critical point will mean it has inflection or nothing at all (has to change sign in order for it to be inflection).
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