prashantakerkar Posted August 6, 2018 Posted August 6, 2018 (edited) https://en.m.wikipedia.org/wiki/Archimedes'_principle Formula derived : F= Rho × g × v rho is liquid constant. How the value of Rho = 100 computed or derived ? Thanks & Regards, Prashant S Akerkar Edited August 6, 2018 by prashantakerkar Content
J.C.MacSwell Posted August 6, 2018 Posted August 6, 2018 (edited) 16 minutes ago, prashantakerkar said: https://en.m.wikipedia.org/wiki/Archimedes'_principle Formula derived : F= rho × g × v rho is constant. How the value of rho = 100 computed or derived ? Thanks & Regards, Prashant S Akerkar rho is density, mass per unit volume of the displaced fluid. Edited August 6, 2018 by J.C.MacSwell
prashantakerkar Posted August 6, 2018 Author Posted August 6, 2018 Thanks. https://en.m.wikipedia.org/wiki/Rho Rho is liquid constant taken as 100 written in wiki. How the value 100 is derived or computed? F= Rho * g * v - Archimedes formula. We have to input Rho value as 100 in the above formula. How Rho a liquid constant as 100 is derived ? Thanks & Regards, Prashant S Akerkar
Sensei Posted August 6, 2018 Posted August 6, 2018 1 minute ago, prashantakerkar said: Rho is liquid constant taken as 100 written in wiki. How the value 100 is derived or computed? F= Rho * g * v - Archimedes formula. We have to input Rho value as 100 in the above formula. How Rho a liquid constant as 100 is derived ? "In the system of Greek numerals, it has a value of 100. " Keyword is Greek numerals! When it's used in physics, it has different, context dependent, meaning. Rho is also symbol of meson particle in high energy physics. https://en.wikipedia.org/wiki/Rho_meson These things should not be mixed and confused together. Analogical situation: imagine Roman numerals. There are e.g. I, V, X, C, M.. Each of these letters has some value 1, 5, 10, 100, 1000..
prashantakerkar Posted August 6, 2018 Author Posted August 6, 2018 Thank you. I agree. But why take a value as 100 and why not say 1,10,1000 etc ? Archimedes has taken value as 100 which is a Roman numeral as 100 for Rho. There are many Roman numerals as 1,10,1000 etc In the formula Archimedes says F=Rho * g * v Why not the below ? F=1*g*v Or F=10×g×v Or F=1000×g×v Or Some other value .... Thanks & Regards, Prashant S Akerkar
prashantakerkar Posted August 6, 2018 Author Posted August 6, 2018 Thanks. Note : Density of water is 997 kg / meter cube. Thanks & Regards, Prashant S Akerkar
prashantakerkar Posted August 6, 2018 Author Posted August 6, 2018 Thanks. Should we take Rho as 100 or 997 or any other value to calculate the Buoyant force in the formula as mentioned by Archimedes ? F = Rho × g × v Thanks & Regards, Prashant S Akerkar
Endy0816 Posted August 6, 2018 Posted August 6, 2018 (edited) Its the density of the fluid. Rho is not meaning 100 here. A fluid is any liquid or gas, so the value will depend. Edited August 6, 2018 by Endy0816
prashantakerkar Posted August 7, 2018 Author Posted August 7, 2018 (edited) Thank you. I.e Archimedes is generalising the formula for Buoyancy force calculation in law of Flotation as F= Density of fluid × g × v and not 100 which is the liquid constant Rho as mentioned in wiki. Is this Incorrect ? F= Rho × g × v Should the formula be corrected as mentioned by Archimedes? Density of fluid will vary from water, oil,milk etc. Thanks & Regards, Prashant S Akerkar Edited August 7, 2018 by prashantakerkar Content.
Bender Posted August 7, 2018 Posted August 7, 2018 1 hour ago, prashantakerkar said: Thank you. I.e Archimedes is generalising the formula for Buoyancy force calculation in law of Flotation as F= Density of fluid × g × v and not 100 which is the liquid constant Rho as mentioned in wiki. Is this Incorrect ? F= Rho × g × v Should the formula be corrected as mentioned by Archimedes? Density of fluid will vary from water, oil,milk etc. Thanks & Regards, Prashant S Akerkar Rho is the density of the fluid. Rho is only 100 in some Greek numeral system I've personally never seen before but is utterly irrelevant here.
prashantakerkar Posted August 7, 2018 Author Posted August 7, 2018 Thanks all for your valuable inputs. Thanks & Regards, Prashant S Akerkar 1
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now