KlausZahn Posted December 8, 2018 Posted December 8, 2018 In my chemistry book there is the task that I should calculate the "average of atomic mass unit" of two isotopes of chlorine. The solution is that the "atomic mass units" are calculated. Then they are added together. (Example: 26,496u + 8,957u = 35,453u). And that is already the result. But if you calculate the average, you still have to divide by two. Why I dont have to divide in this calculation? Thanks for your answers
studiot Posted December 8, 2018 Posted December 8, 2018 20 minutes ago, KlausZahn said: In my chemistry book there is the task that I should calculate the "average of atomic mass unit" of two isotopes of chlorine. The solution is that the "atomic mass units" are calculated. Then they are added together. (Example: 26,496u + 8,957u = 35,453u). And that is already the result. But if you calculate the average, you still have to divide by two. Why I dont have to divide in this calculation? Thanks for your answers Can you post the question? 26 and 8 are not isotpic masses for chlorine or any element. Nor does any element have 26 protons and only 8 neutrons, or the other way round.
KlausZahn Posted December 8, 2018 Author Posted December 8, 2018 34 minutes ago, studiot said: Can you post the question? 26 and 8 are not isotpic masses for chlorine or any element. Nor does any element have 26 protons and only 8 neutrons, or the other way round. The question is in german. I have to calculate the medium atomic mass of natural chlorine. The isotops are Cl-37 (24,23%) and Cl-35 (75,55%)
Sensei Posted December 8, 2018 Posted December 8, 2018 (edited) 2 hours ago, KlausZahn said: But if you calculate the average, you still have to divide by two. Why I dont have to divide in this calculation? In mathematics, if you calculate average from some numbers, you indeed add them together, then divide by their quantity: ( x1 + x2 + ... xn ) / n But in the case of calculation of "average Chlorine mass" it's not the case, as you use percentages of abundance. They sum to one (100%). 0.7577 + 0.2423 = 1 If you would be able to count the all atoms to the single one, you could get such equation: ( 34.969u * 7577 + 36.966u * 2423 ) / 10000 (if you would have 10 thousands Chlorine atoms) Edited December 8, 2018 by Sensei
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