MaximT Posted March 28, 2019 Posted March 28, 2019 I want to discuss the possibility to build an elevator on the Moon surface... There are some data: Basically, the speed on the surface will have to follow this rule: (where u = 4.905E12 m²/s) The limitation, for the length of the cable is 4,500 km high...
swansont Posted March 28, 2019 Posted March 28, 2019 You have not explained what your variables are or how they relate to your video, or your spreadsheet. Also your equation can’t work, since it has the wrong units.
MaximT Posted March 28, 2019 Author Posted March 28, 2019 (edited) 6 hours ago, swansont said: your equation can’t work, since it has the wrong units. In fact, you are right, My mistake, sorry: In celestial mechanics, the standard gravitational parameter μ of a celestial body is the product of the gravitational constant G and the mass M of the body. μ=GM For several objects in the Solar System, the value of μ is known to greater accuracy than either G or M.[11] The SI units of the standard gravitational parameter are m3s−2. However, units of km3s−2 are frequently used in the scientific literature and in spacecraft navigation 15 hours ago, MaximT said: Basically, the speed on the surface will have to follow this rule: (where u = 4.905E12 m³/s²) This equation is derived from the circular orbit speed, as described in literacy: 15 hours ago, MaximT said: The limitation, for the length of the cable is 4,500 km high... It's simply the breaking strength, in the spreadsheet, related to the mass of the cable, In it's most simple expression, but with centripetal force applied. Edited March 28, 2019 by MaximT
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