Rebeka Posted April 25, 2019 Posted April 25, 2019 Hello everyone! I was wondering if anyone could show me how the amide on the drug Ibrutinib would react with LiAlH4? I understand how amide would normally react with LiAlH4 but I am confused as to how I would react this amide because of the placement of the N. Any help would be greatly appreciated. Thank you I've attached an image of Ibrutinib so you can see the amide that I am trying to react !
chenbeier Posted April 25, 2019 Posted April 25, 2019 To make it easy C=O in the amide will be converted to CH2
BabcockHall Posted April 29, 2019 Posted April 29, 2019 What do you mean by placement of the N, and why do you think it might be important?
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