The Discovery and Utilization of Relativity Energy --A Whole New Energy Source

[Yalin]

The Discovery and Utilization of Relativity Energy --A Whole New Energy Source

My theory and experiment are inspired by war battles in ancient times. Picture this scene :warriors on horseback brandishing machetes dash toward enemy infantry troops, slashing all soldiers in their path. Suppose a horse gallops at speed a, a machete is wielded at speed b, then an enemy is slashed at speed c that puts a and b together. If not on horseback, a warrior wields a machete directly at speed c, the energy needed will be 1/2mc2. Suppose the mass value of the machete is 2,then the energy consumed is c2=(a+b)2. If the speed is accelerated in two steps, with additional acceleration based on the movement of one object, the energy used is 1/2ma2+1/2mb2. When the mass value of the machete is substituted into the equation, then energy used is a2+b2. According to the mathematical formula (a+b)2＝a2+b2＋2ab, the amounts of energy consumed through these two accelerating ways are different, while the kinetic energy c2 achieved is the same. The 2ab of energy saved through the means of slashing enemies on a galloping horse is called, for the time being, relativity energy. the experiment of electricity generation by harnessing relativity energy Let's make some modifications to an ordinary generator by changing it's rotor into a small wheel with a hollow tube on the edge, and forming the magnate blocks into something like a train that runs on the circular hollow track, as shown in fig. 1 attached. When the wheel with a tube moves in circles propelled by the dynamic system, the train formed by the magnate blocks also moves in the same direction driven by a storage battery, the second dynamic system. Suppose the speed of the circular track is v1 and the train of magnate blocks v2, then the speed of the train rotor, in relation to the stator, is v1 and v2 added up. Conclusion: in the experiment, the mass of te is m, the amounts of energy consumed by the circular track and magnate train for acceleration are 1/2mv12 and 1/2mv22 respectively, while the electricity energy produced is 1/2m(v1＋v2)2. Suppose v1 is a and v2 b, then (a+b)2>a2+b2 is deduced. The 2ab is the energy gained.

[Strange]

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Moderator Note

Moved to Speculations

 

[swansont]

1. c is reserved for the speed of light, so you should not use it in your analysis.

2. if you are going to use variables for speed, you should do for m as well, rather than assigning it a numerical value.

3. You need to use proper notation for squared values (x^2 or x² or use LaTex) to avoid confusion, especially because you've used m=2, and now you have 2's floating around everywhere

4. writing this out as a paragraph makes it difficult to parse.

We already know that KE is frame-dependent (it's not invariant), so you need to do analyses in a single frame in order to get valid results. It's not clear to me that you aren't mixing frames.

[Bufofrog]

10 hours ago, Yalin said:

Suppose the mass value of the machete is 2,then the energy consumed is c2=(a+b)2. If the speed is accelerated in two steps, with additional acceleration based on the movement of one object, the energy used is 1/2ma2+1/2mb2. When the mass value of the machete is substituted into the equation, then energy used is a2+b2. According to the mathematical formula (a+b)2＝a2+b2＋2ab,

The first part is correct \( c^2=(a+b)^2 \).

The problem appears to be your incorrect use of the quadratic formula.  To use the quadratic formula the equation must be in the form of \(ax^2+bx+c=0\).  Your equation does not equal zero so you cannot expand \( (a+b)^2 \) using the QF.

Edited June 30, 2019 by Bufofrog

[Yalin]

The Discovery and Utilization of Relativity Energy --A Whole New Energy Source

My theory and experiment are inspired by war battles in ancient times.

Picture this scene: warriors on horseback brandishing machetes dash toward enemy infantry troops, slashing all soldiers in their path. Suppose a horse gallops at speed a, a machete is wielded at speed b, then an enemy is slashed at speed c that puts a and b together.

If not on horseback, a warrior wields a machete directly at speed c, the energy needed will be 1/2mc². Suppose the mass value of the machete is 2,then the energy consumed is c²=(a+b)².

If the speed is accelerated in two steps, with additional acceleration based on the movement of one object, the energy used is 1/2ma²+1/2mb². When the mass value of the machete is substituted into the equation, then energy used is a²+b². 

According to the mathematical formula (a+b)²=a²+2ab+b²，the amounts of energy consumed through these two accelerating ways are different, while the kinetic energy c² achieved is the same.

The 2ab of energy saved through the means of slashing enemies on a galloping horse is called, for the time being, relativity energy.

The experiment of electricity generation by harnessing relativity energy . 

Let's make some modifications to an ordinary generator by changing it's rotor into a small wheel with a hollow tube on the edge, and forming the magnate blocks into something like a train that runs on the circular hollow track, as shown in fig. 1 attached.

When the wheel with a tube moves in circles propelled by the dynamic system, the train formed by the magnate blocks also moves in the same direction driven by a storage battery, the second dynamic system.

Suppose the speed of the circular track is v1 and the train of magnate blocks v2, then the speed of the train rotor, in relation to the stator, is v1 and v2 added up.

Conclusion: in the experiment, the mass of te is m, the amounts of energy consumed by the circular track and magnate train for acceleration are 1/2mv1² and 1/2mv2² respectively, while the electricity energy produced is 1/2m(v1＋v2)².

Suppose v1 is a and v2 b, then (a+b)²>a²+b² is deduced. The 2ab is the energy gained.

Edited July 1, 2019 by Yalin

[Ghideon]

1 hour ago, Yalin said:

If the speed is accelerated in two steps, with additional acceleration based on the movement of one object, the energy used is 1/2ma²+1/2mb². When the mass value of the machete is substituted into the equation, then energy used is a²+b². 

According to the mathematical formula (a+b)²=a²+2ab+b²，the amounts of energy consumed through these two accelerating ways are different, while the kinetic energy c² achieved is the same.

The 2ab of energy saved through the means of slashing enemies on a galloping horse is called, for the time being, relativity energy.

Math is incorrect and you are mixing frames of reference as pointed out by @Bufofrog and @swansont.

I think you could use some basic logic to see that the idea is likely incorrect. Lets assume that your idea is correct; acceleration in steps will result in more kinetic energy relative to the ground that accelerating in one step. Apply the idea to a car and accelerate the car in many small steps. The result is that the additional "2ab" called relativity energy in your idea will occur many times? But: Do you think a car traveling at speed v after being accelerated in steps are harder to stop* than a car that was accelerated in one go? How come no one notices this in daily life or on a racetrack?
Or: Accelerate in steps and then stop in one smooth step. Repeat. Where does your "2ab" go? The stopping is just acceleration in negative direction and according to your idea the amounts of kinetic energy will not be equal.
 

*) analogous to the enemy getting hit harder by the machete that was accelerated in steps

[swansont]

3 hours ago, Yalin said:

 If the speed is accelerated in two steps, with additional acceleration based on the movement of one object, the energy used is 1/2ma²+1/2mb². When the mass value of the machete is substituted into the equation, then energy used is a²+b². 

Nope.