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Posted (edited)

If you have 1 kg Oleum (20% SO3 dissolved in 100% H2SO4) then you have 200 g of sulfur trioxide and 800 g sulfuric acid.  With the molare weight of 80 g/mol for SO3  you get 2,5 mol.

You need also 2,5 mol water according H2O + SO3 => H2SO4 . This is equal to 45 g. So take 45 g = 45 ml water first!!  and add carefully the Oleum.

Edited by chenbeier
Posted

Given the extremely violent reaction of  oleum with water it's probably better to add the oleum to ice.

It may also be a better bet to let it absorb water from the air (until it gains the right mass), but the fumes would be a problem.

 

Fundamentally, if you can't do basic chemistry like the calculation above, you shouldn't be working with oleum.

 

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