DimaMazin Posted August 17, 2019 Posted August 17, 2019 (edited) t = ((dx)2/c2+q2)1/2 t is time dx is quantity of motion c is velocity of light q is quantity of counteraction of forces to motion q = t' for traveling object Edited August 17, 2019 by DimaMazin
Strange Posted August 17, 2019 Posted August 17, 2019 44 minutes ago, DimaMazin said: q is quantity of counteraction of forces to motion What does that mean? What units does q have? Is it the same as inertia? Quote q = t' for traveling object You haven't specified what t' is. How does any of this relate to the speed of this travelling object? Once again, you have thrown together a random equation. What is any of the supposed to mean?
Ghideon Posted August 17, 2019 Posted August 17, 2019 1 hour ago, DimaMazin said: dx is quantity of motion In addition to what @Strange wrote; your definition looks circular. As far as I know motion, in physics*, is the change in position of an object with respect to its surroundings in a given interval of time. How do you define motion to be able to define time to be dependent on motion? *) paraphrase of wikipedia/Motion
DimaMazin Posted August 17, 2019 Author Posted August 17, 2019 55 minutes ago, Strange said: What does that mean? What units does q have? Is it the same as inertia? You haven't specified what t' is. How does any of this relate to the speed of this travelling object? Once again, you have thrown together a random equation. What is any of the supposed to mean? Clock correctly shows time only then when their motion of arrows and mechanism counteraction to the motion correspond to my formula. t' is time of traveler q is not Newtonian inertia. Unit of q is second, maybe quantum phisicits will create another unit. Energy should travel at c without forces counteraction. 23 minutes ago, Ghideon said: In addition to what @Strange wrote; your definition looks circular. As far as I know motion, in physics*, is the change in position of an object with respect to its surroundings in a given interval of time. How do you define motion to be able to define time to be dependent on motion? *) paraphrase of wikipedia/Motion We can define change of distance without known time.
Strange Posted August 17, 2019 Posted August 17, 2019 8 minutes ago, DimaMazin said: Clock correctly shows time only then when their motion of arrows and mechanism counteraction to the motion correspond to my formula. I have no idea what that is supposed to mean.
swansont Posted August 17, 2019 Posted August 17, 2019 24 minutes ago, DimaMazin said: Energy should travel at c without forces counteraction. A ball of mass m, moving at speed v, has mass+kinetic energy. Why/how does that energy move at c?
Ghideon Posted August 17, 2019 Posted August 17, 2019 29 minutes ago, DimaMazin said: We can define change of distance without known time. How?
beecee Posted August 17, 2019 Posted August 17, 2019 47 minutes ago, DimaMazin said: We can define change of distance without known time. Change [of distance] occurs in time. Time is not specifically a result of change. imho.
swansont Posted August 17, 2019 Posted August 17, 2019 3 hours ago, DimaMazin said: q is quantity of counteraction of forces to motion q = t' for traveling object If the motion is at constant velocity, there is no force, so presumably no “counteraction” Thus q = 0 You haven’t defined t’
DimaMazin Posted August 17, 2019 Author Posted August 17, 2019 Let's solve such task: We know distance between the Earth and green planet. Green traveler turned on its clock at start of travel to us. The traveler was traveling at different and unknown speeds. Time of start of the travel is unknown and we should define it. The green traveler has errieved to us and showed time of traveling clock. I can simply solve the task using my equation. Can you solve the task simpler?
Ghideon Posted August 17, 2019 Posted August 17, 2019 (edited) 14 minutes ago, DimaMazin said: Green traveler turned on its clock How did green traveler define time to be able to create a clock? I maybe do not understand what you mean when you use the Word ”definition” in your math. Edited August 17, 2019 by Ghideon
Strange Posted August 17, 2019 Posted August 17, 2019 29 minutes ago, DimaMazin said: Let's solve such task: We know distance between the Earth and green planet. Green traveler turned on its clock at start of travel to us. The traveler was traveling at different and unknown speeds. Time of start of the travel is unknown and we should define it. The green traveler has errieved to us and showed time of traveling clock. I can simply solve the task using my equation. Can you solve the task simpler? There isn't enough information (ie. no numbers). But feel free to show how your equation "solves" this, instead of just claiming that it does. 1
DimaMazin Posted August 18, 2019 Author Posted August 18, 2019 1 hour ago, Strange said: There isn't enough information (ie. no numbers). But feel free to show how your equation "solves" this, instead of just claiming that it does. We can use variables dx is distance between the planets t1 is time of start of travel t2 is time of end of travel t' is time of traveling clock at end of travel t2 - t1 =(( dx)2/c2 +t'2)1/2 We need to define t1 t1=t2 - ((dx)2/c2 + t'2)1/2 3 hours ago, swansont said: If the motion is at constant velocity, there is no force, so presumably no “counteraction” Thus q = 0 You haven’t defined t’ Forces exist in mass. Mass can not exist without forces.
polis.aniftos@gmail.com Posted August 18, 2019 Posted August 18, 2019 8 hours ago, DimaMazin said: t = ((dx)2/c2+q2)1/2 t is time dx is quantity of motion c is velocity of light q is quantity of counteraction of forces to motion q = t' for traveling object q is temporal inertia in an expanding universe where time is the expansion of space (suggestion based according to the above formula if we multiply and divide the right part by x)
moth Posted August 18, 2019 Posted August 18, 2019 (edited) 2 hours ago, DimaMazin said: t1 is time of start of travel t2 is time of end of travel t' is time of traveling clock at end of travel t2 - t1 =(( dx)2/c2 +t'2)1/2 In the clock's frame of reference, shouldn't t`=tsub2 - tsub1? Edited August 18, 2019 by moth
Strange Posted August 18, 2019 Posted August 18, 2019 8 hours ago, DimaMazin said: We can use variables dx is distance between the planets t1 is time of start of travel t2 is time of end of travel t' is time of traveling clock at end of travel t2 - t1 =(( dx)2/c2 +t'2)1/2 We need to define t1 t1=t2 - ((dx)2/c2 + t'2)1/2 Now show that this produces the same results as SR.
DimaMazin Posted August 18, 2019 Author Posted August 18, 2019 12 hours ago, Ghideon said: How? You can measure short distance by ruler, then you can define dx. Scientists can measure large dx of light by brightness of supernova. 6 hours ago, moth said: In the clock's frame of reference, shouldn't t`=tsub2 - tsub1? Then speed of travel=0
Strange Posted August 18, 2019 Posted August 18, 2019 13 minutes ago, DimaMazin said: You can measure short distance by ruler, then you can define dx. Which frame of reference is dx measured in? 17 minutes ago, Strange said: Now show that this produces the same results as SR. Or show how you derived your equation from SR. I am assuming you didn't just make it up from thin air.
swansont Posted August 18, 2019 Posted August 18, 2019 11 hours ago, DimaMazin said: Forces exist in mass. Mass can not exist without forces. So? Internal forces don’t affect motion. Why would they affect time? Why would time run differently for a hydrogen atom than a carbon atom, moving at the same speed?
DimaMazin Posted August 18, 2019 Author Posted August 18, 2019 9 hours ago, Strange said: Which frame of reference is dx measured in? Or show how you derived your equation from SR. I am assuming you didn't just make it up from thin air. t'c/(c2 - v2)1/2 = t t2=t'2c2/(c2-v2) t2=t'2c2/(c2-dx2/t2) t'2c2/(t2c2-dx2)=1 t'2c2=t2c2-dx2 t'2c2/c2+dx2/c2=t2 t2=dx2/c2+t'2 t=(dx2/c2+t'2)1/2 We can not use the equation for solve of my task because we should know more data 7 hours ago, swansont said: So? Internal forces don’t affect motion. Why would they affect time? Why would time run differently for a hydrogen atom than a carbon atom, moving at the same speed? I am wrong there.
Ghideon Posted August 18, 2019 Posted August 18, 2019 I have misinterpreted the intention of the headline "Time definition". You are trying to calculate a time t? I thought you were posting a definition of time; so my comments probably don't apply.
DimaMazin Posted August 24, 2019 Author Posted August 24, 2019 On 8/18/2019 at 11:08 PM, Ghideon said: I have misinterpreted the intention of the headline "Time definition". You are trying to calculate a time t? I thought you were posting a definition of time; so my comments probably don't apply. t = q/m t is time of observer q is quantity of counteraction of forces to motion of motionlees object m is mass of motionless object
Ghideon Posted August 24, 2019 Posted August 24, 2019 2 hours ago, DimaMazin said: t = q/m t is time of observer q is quantity of counteraction of forces to motion of motionlees object m is mass of motionless object That does not match earlier statements. What units does t, q and m have? Earlier posts: On 8/17/2019 at 7:17 PM, DimaMazin said: q = t' for traveling object and On 8/17/2019 at 9:36 PM, DimaMazin said: Unit of q is second, maybe quantum phisicits will create another unit. So what is q?
DimaMazin Posted August 24, 2019 Author Posted August 24, 2019 1 hour ago, Ghideon said: That does not match earlier statements. What units does t, q and m have? Earlier posts: and So what is q? t has second m has kilogram q has second * kilogram If quantity of counteraction of forses to motion doesn't exist then how Swansont defined different quantities of it for different masses?
Ghideon Posted August 24, 2019 Posted August 24, 2019 9 minutes ago, DimaMazin said: t has second m has kilogram q has second * kilogram And 4 hours ago, DimaMazin said: q is quantity of counteraction of forces to motion of motionlees object What kind of "force" has kg*s as unit? Compare definition of Newton: [math] kg*m*s^{-2} [/math] 4 hours ago, DimaMazin said: m is mass of motionless object If object is motionless then there is no force acting on it so q=0 and therefore t = q/m = 0. Do you mean that time stands still for objects at rest?
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