Rachel Maddiee Posted September 12, 2019 Posted September 12, 2019 Solve -3(a+3) +5 (3-a) = -50 I can’t apply Properties of Equality.
studiot Posted September 12, 2019 Posted September 12, 2019 (edited) 1 hour ago, Rachel Maddiee said: Solve -3(a+3) +5 (3-a) = -50 I can’t apply Properties of Equality. Why not ? I make a = 7 Edited September 12, 2019 by studiot 1
Sensei Posted September 12, 2019 Posted September 12, 2019 (edited) First, you need to multiply what you have prior bracket with what is inside of bracket e.g. -3(a+3) = -3*a-3*3 = -3a-9 then the same with second one, 5(3-a)=5*3-5a=15-5a then move the all numbers to the right side, changing signs -50+9-15=-56 sum the all a on the left side -3a-5a=-8a so you have finally -8a=-56 divide by -8 either side a=-56/(-8)=56/8=7 ps. It's not geometry, but algebra. Linear equation with single unknown. https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-solving-equations Edited September 12, 2019 by Sensei 1
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