JamesBennettBeta Posted October 11, 2019 Posted October 11, 2019 A power-law fluid, or the Ostwald–de Waele relationship, is a type of generalized Newtonian fluid (time independent Non-Newtonian fluid) for which the shear stress, τ, is given by τ = A(du/dy)n + B Where A, B and n are constants that depend upon the type of fluid and conditions imposed on the flow. Comment on the value of these constants so that the fluid may behave as: I) an ideal fluid II) a Newtonian fluid III)a non-Newtonian fluid
studiot Posted October 11, 2019 Posted October 11, 2019 (edited) That is the question. You surely must have some ideas of some of them, especially the value of B for parts (I) and (II) So what have you done so far? What is Newtons law of viscosity? Edited October 11, 2019 by studiot
JamesBennettBeta Posted October 12, 2019 Author Posted October 12, 2019 1. A=0 B=? n=? In an ideal fluid the viscosity should be equal to zero. 2. A=? B=? n=1 In a Newtonian fluid the flow behavior index is equal to 1 (Experimentally) 3. A=? B=? n≠1 In a non-Newtonian fluid the flow behavior index is bot equal to 1 This is the far that I could understand.
studiot Posted October 12, 2019 Posted October 12, 2019 (edited) 18 hours ago, JamesBennettBeta said: is a type of generalized Newtonian fluid (time independent Non-Newtonian fluid) How can something be generalised Newtonian and non Newtonian ? I did ask you to state Newton's Law of Viscoscity. Using your symbols it is [math]\tau = A\frac{{du}}{{dy}}[/math] or in words shear stress = a constant * rate of shear It is also a straight line through the origin. So Newton's law has B = 0 What about the other constants in your test equation? Can you now allocate these for Newton's Law? You should sketch this graph, plotting shear strees against on the y axis rate of shear on the x axis. So to generalise Newton.s Law What will the introduction of a constant B do to any such plot? What about the values of n and A ? Edited October 12, 2019 by studiot
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