1/0=+/-infinity

[Andrew26]

It can be shown that as x approaches 0 from the right side, 1/x will approach 1/0 and apporach positive infinity. And it can be shown that as -x approaches 0 from the left side, -1/x will approach negative infinity and apporach -1/0, which is equal to (-1/-1)*-1/0 equals 1/0, since 0 is neither positive or negative.

Showing that 1/0 is not even a number, and does not represent a distinct point on the real number line.

 

[mathematic]

Division by 0 is illegal, so there is no such number!

[Endy0816]

0/b = 0

Solve for b.

[Strange]

7 hours ago, Endy0816 said:

0/b = 0

Solve for b.

You can b whatever you want to b

[Endy0816]

2 hours ago, Strange said:

You can b whatever you want to b

But you can't b a zero!

[mistermack]

55 minutes ago, Endy0816 said:

But you can't b a zero!

There's nothing stopping you.

[Andrew26]

15 hours ago, Endy0816 said:

0/b = 0

Solve for b.

The question here is what is b/0. 

[Endy0816]

8 hours ago, Andrew26 said:

The question here is what is b/0. 

 

the problem is you are dividing by zero which has undefined elements to it.

0 = 0/4 = 0/-2579 = 0/323i = 0/π = ...

From a simple seeming 1/0 you can forever pull any number(excluding zero) from below, preventing you from even saying it equals anything in particular even if it heads that way.

1/0 = 1/((((0/.33)/9i)/-196)/5)

consider 0a and a-a for added fun.

[Andrew26]

14 hours ago, Endy0816 said:

 

the problem is you are dividing by zero which has undefined elements to it.

0 = 0/4 = 0/-2579 = 0/323i = 0/π = ...

From a simple seeming 1/0 you can forever pull any number(excluding zero) from below, preventing you from even saying it equals anything in particular even if it heads that way.

1/0 = 1/((((0/.33)/9i)/-196)/5)

consider 0a and a-a for added fun.

As stated in the OP, 1/0 equals +/-infinity as a limit. 

Your post is impertinent here