willem Posted November 21, 2019 Posted November 21, 2019 (edited) Hello, I am currently doing my major in the feild of organic chemistry but cannot seem to find the thermal conductivity of 2-propanol/isopropyl in it's gaseous state. If anyone knows how to calculate this or would be able to help me find where to look I would be very grateful! Edited November 21, 2019 by willem
Ghideon Posted November 21, 2019 Posted November 21, 2019 3 minutes ago, willem said: help me find where to look Is this what you are looking for?http://www.ddbst.com/en/EED/PCP/TCN_C95.php, Dortmund Data Bank, Thermal Conductivity of n-Propyl and Isopropyl Alcohols at Various Temperatures and Pressures
willem Posted November 21, 2019 Author Posted November 21, 2019 2 minutes ago, Ghideon said: Is this what you are looking for?http://www.ddbst.com/en/EED/PCP/TCN_C95.php, Dortmund Data Bank, Thermal Conductivity of n-Propyl and Isopropyl Alcohols at Various Temperatures and Pressures I just edited the post, I forgot to add that it was in its gaseous state, my bad. If you could help me with this I would be beyond grateful. But thanks for the quick reply! I have looked through multiple CRC handbooks at the gas thermal conductivity section.
studiot Posted November 21, 2019 Posted November 21, 2019 This is from the 15 th Edition of Lange's handbook of Chemistry (there are at least 2 newer editions) The units are Quote 5.8 THERMAL CONDUCTIVITY TABLE 5.24 Thermal Conductivities of Gases as a Function of Temperature The coefficient k, expressed in J · sec1 · cm1 · K1, is the quantity of heat in joules, transmitted per second through a sample one centimeter in thickness and one square centimeter in area when the temperature difference between the two sides is one degree kelvin (or Celsius). The tabulated values are in microjoules. To convert to microcalories, divide values by 4.184. To convert to mW · m1 · K1, divide values by 10. It's a bit skimpy, at a pinch you could compare with other close members of the homologous series for which more data is available. Does this help? 1 hour ago, willem said: Hello, I am currently doing my major in the feild of organic chemistry but cannot seem to find the thermal conductivity of 2-propanol/isopropyl in it's gaseous state. If anyone knows how to calculate this or would be able to help me find where to look I would be very grateful! This is from the 15 th Edition of Lange's handbook of Chemistry (there are at least 2 newer editions) The units are Quote 5.8 THERMAL CONDUCTIVITY TABLE 5.24 Thermal Conductivities of Gases as a Function of Temperature The coefficient k, expressed in J · sec1 · cm1 · K1, is the quantity of heat in joules, transmitted per second through a sample one centimeter in thickness and one square centimeter in area when the temperature difference between the two sides is one degree kelvin (or Celsius). The tabulated values are in microjoules. To convert to microcalories, divide values by 4.184. To convert to mW · m1 · K1, divide values by 10. It's a bit skimpy, at a pinch you could compare with other close members of the homologous series for which more data is available. Does this help?
willem Posted November 22, 2019 Author Posted November 22, 2019 11 hours ago, studiot said: This is from the 15 th Edition of Lange's handbook of Chemistry (there are at least 2 newer editions) The units are It's a bit skimpy, at a pinch you could compare with other close members of the homologous series for which more data is available. Does this help? This is from the 15 th Edition of Lange's handbook of Chemistry (there are at least 2 newer editions) The units are It's a bit skimpy, at a pinch you could compare with other close members of the homologous series for which more data is available. Does this help? Thanks a lot! That was exactly what I was looking for. I only had the 13th edition of Lange's handbook available where it did not say. You really saved my day! Thank you!
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now