Rachel Maddiee Posted December 22, 2019 Posted December 22, 2019 Is this the correct equation for alpha decay? 243/93 Am —> 239/93Np + 4/2He
Sensei Posted December 22, 2019 Posted December 22, 2019 24 minutes ago, Rachel Maddiee said: Is this the correct equation for alpha decay? 243/93 Am —> 239/93Np + 4/2He No. Almost. Pay better attention to numbers..
John Cuthber Posted December 22, 2019 Posted December 22, 2019 7 hours ago, Rachel Maddiee said: What is incorrect? A typo, but you need to fix it.
swansont Posted December 23, 2019 Posted December 23, 2019 5 hours ago, Rachel Maddiee said: 95 protons And you wrote "243/93 Am" which is the mistake people were hinting about. Z didn't change in the reaction, but it must decrease by 2 in alpha decay
Avy213 Posted December 23, 2019 Posted December 23, 2019 Not at all..... The atomic no must reduce by 2
swansont Posted December 23, 2019 Posted December 23, 2019 9 minutes ago, Avy213 said: Not at all..... The atomic no must reduce by 2 Z is the atomic number, so...
swansont Posted December 23, 2019 Posted December 23, 2019 3 hours ago, Rachel Maddiee said: So how should I write it? Change the 93 to 95 for Am i.e. 243/95 Am 1
Avy213 Posted December 25, 2019 Posted December 25, 2019 On 12/23/2019 at 6:05 PM, swansont said: Z is the atomic number, so... Of course,sir...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now